What number best completes both equations? 2/3÷3/10=_

Is how many sixth graders attend your school a statistical question?

HACTEHA [7]

Yes, any question that involves numbers would be a statistical question.

8 0

3 years ago

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What are the graphs of y=sinx and y=cosx in the interval from -2 pi to 2 pi?

g100num [7]

I used Excel to create the tables and the graphs.

I attached both the tables and the graphs.

You should replace the numbers of the x-axis (in both graphs) by the numbers as a fraction of pi. Those numbers are also included in the table, so you should not have problems with that.

Open and see tha file attached with the answer to your question..

Download pdf

5 0

3 years ago

Please solve, -7x+8=-4(x+1)

omeli [17]

Answer: $x=4$

Simplify both sides of the equation.

$-7x+8=-4(x+1)\\-7x+8=(-4)(x)+(-4)(1)(Distribute)\\-7x+8=-4x+-4$

Add 4x to both sides

$-7x+8+4x=-4x-4+4x\\-3x+8=-4$

Subtract 8 from both sides

$-3x+8-8=-4-8\\-3x=-12$

Divide both sides by -3

$-3x/-3=-12/-3\\x=4$

5 0

2 years ago

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Find the cost per visit to the nearest cent: Health and Heart Club, $259 per year, 3 visits per week. a. $1.66 b. $7.19 c. $156

vagabundo [1.1K]

Answer:

a. $1.66

Step-by-step explanation:

We have been given that Health and Heart Club charges $259 per year. A person has 3 visits per week. We are asked to find the cost of per visit to Health and Heart Club.

We know that there are 52 weeks in one year. So total visits in one year would be 3 times 52 that $156$ visits.

Now, we will divide total cost by 156 to find cost per visit.

$\text{Cost per visit}=\frac{\$259}{156}$

$\text{Cost per visit}=\$1.660256$

Rounding to nearest hundredths, we will get:

$\text{Cost per visit}\approx \$1.66$

Therefore, the cost per visit is $1.66 and option 'a' is the correct choice.

5 0

3 years ago

Three machines A, B, and C produce 55%, 25% and 20% respectively. The percentages of defective output are 3.5%, 4.5% and 5.5%. I

pishuonlain [190]

We are given the following information concerning the three production machines;

$\begin{gathered} Of\text{ the total production;} \\ A=55\text{ \%}=0.55 \\ B=25\text{ \%}=0.25 \\ C=20\text{ \%}=0.20 \end{gathered}$

Also, we are given the percentage of defective output as follows;

$\begin{gathered} A=3.5\text{ \%}=0.035 \\ B=4.5\text{ \%}=0.045 \\ C=5.5\text{ \%}=0.055 \end{gathered}$

Therefore, if an item is selected randomly, the probability that the item is defective would be;

$\begin{gathered} P\lbrack defective\rbrack=(0.55\times0.035)+(0.25\times0.045)+(0.20\times0.055) \\ P\lbrack\text{defective\rbrack}=0.01925+0.01125+0.011 \\ P\lbrack\text{defective\rbrack}=0.0415 \end{gathered}$

ANSWER:

The probability that the item is defective would be 0.0415

6 0

1 year ago

What number best completes both equations? 2/3÷3/10=_ _×3/10=2/3