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Paraphin [41]
3 years ago
10

Sonya expected to get $60 for her birthday ,but she only got $40.What was the percentage decrease of the amount Sonya recieved?

Mathematics
2 answers:
kow [346]3 years ago
7 0
Are you asking about the percent of change?if so the answer is 33.3%.
dalvyx [7]3 years ago
4 0
The answer is $100 to the answer
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Is it 5^6 - 5^11 = 5x × (1-5y)?
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1/3125 = 5(x-5y)
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6 0
3 years ago
Find the value of the expression 9 x 7 + 8 divided by 2
Softa [21]

Answer:

35.5 i'm pretty sure

Step-by-step explanation:

because 9 times 7 is 63.  63 plus 8 is 71 and 71/2 is 35.5

4 0
3 years ago
What is 7/4 as a mixed number
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3 years ago
Finding Present Value In Exercise,complete the table to determine the amount of money P that should be invested at rate r to pro
valkas [14]

Answer:

Step-by-step explanation:

The principal was compounded monthly. This means that it was compounded 12 times in a year. So

n = 12

The rate at which the principal was compounded is 4%. So

r = 4/100 = 0.04

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years. The total amount is given as $100000.

1) When t is 1,

100000 = P(1+0.04/12)^12×1

100000 = P(1+0.0033)^12

100000 = P(1.0033)^12

P = 100000/1.04

P = $96154

2) When t is 10

100000 = P(1+0.04/12)^12×10

100000 = P(1+0.0033)^120

100000 = P(1.0033)^120

P = 100000/1.485

P = $67340

3) When t is 20

100000 = P(1+0.04/12)^12×20

100000 = P(1+0.0033)^240

100000 = P(1.0033)^240

P = 100000/2.2

P = $45455

4) When t is 30

100000 = P(1+0.04/12)^12 × 30

100000 = P(1+0.0033)^360

100000 = P(1.0033)^360

P = 100000/3.274

P = $30544

5) When t is 40

100000 = P(1+0.04/12)^12 × 40

100000 = P(1+0.0033)^480

100000 = P(1.0033)^480

P = 100000/4.862

P = $20568

6)When t is 50

100000 = P(1+0.04/12)^12 × 50

100000 = P(1+0.0033)^600

100000 = P(1.0033)^600

P = 100000/7.22

P = $13850

5 0
3 years ago
By which numbers (4,6,8 or 9) are the following numbers divisible?
kaheart [24]

Answer:

option a as last digit even a d come in 3 table

6 0
3 years ago
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