Answer:
He gets 32, $10 bills.
Step-by-step explanation:
He puts in $630.
3 times $50 equals $150.
8 times $20 equals $160.
$150 plus $160 equals $310.
$630 minus $310 equals $320.
$320 divided by 10 equals 32.
So he gets 32, $10 bills.
Answer:
6*(61^2) and 61^3
Step-by-step explanation:
If the squares have a side length of 61 (assuming this is a cube) our surface area is 6*(61^2) because each side is a square and there are six sides.
As for the volume, we have 61^3.
Hope this was helpful.
~cloud
Draw the tape diagram: a long rectangle and divide it into 4 squares in a row.The whole rectangle represents 24 (as a whole number), you're dividing it into 4 parts because you want to know what is 1/4 of it.Now, to find the value of each square: 24:4 = 6.Put the number 6 in each square, and you have found your result.1/4 of 24 is 6.
Answer:
0.258819045...
Step-by-step explanation:
just plug it into a calculator
Answer:
![Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%204.97%20-%281.61%29%5E2%20%3D2.3779)
And the deviation would be:

Step-by-step explanation:
For this case we have the following distribution given:
X 0 1 2 3 4 5 6
P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02
For this case we need to find first the expected value given by:

And replacing we got:

Now we can find the second moment given by:

And replacing we got:

And the variance would be given by:
![Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%204.97%20-%281.61%29%5E2%20%3D2.3779)
And the deviation would be:
