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kow [346]
3 years ago
9

Five less than 4/5 of a number is at most -29

Mathematics
1 answer:
Mrrafil [7]3 years ago
8 0

Answer:

-30

Step-by-step explanation:

(-24)-5 = -29

-24/4 = -6

-6*5 = -30

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Can you please help me with this question
Naily [24]

Answer:

Paid her: 24 because 14+6+4=24

Step-by-step explanation:

3 0
2 years ago
Caleb bought groceries and paid
lutik1710 [3]

Answer:

Price of Caleb's groceries before tax= $6.4

Step-by-step explanation:

Let price of groceries before tax be = $ x

Sales tax % = 2.5%

Sales tax applied = 2.5\% \ of\ x = \frac{25}{100}\times x = \frac{25}{100} x

Actual sales tax paid = $1.60

∴ \frac{25}{100}x=1.60

Multiplying both sides by 100.

100\times \frac{25}{100}x=1.60\times 100

25x=160

Dividing both sides by 25.

\frac{25x}{25}=\frac{160}{25}

x=6.4

∴ Price of groceries before tax= $6.4

8 0
3 years ago
Read 2 more answers
Solve each equation by completing the square <br>r² = –12r - 35​
Fittoniya [83]

Answer:

r = - 7, r = - 5

Step-by-step explanation:

Given

r² = - 12r - 35 ( add 12r to both sides )

r² + 12r = - 35

To complete the square

add ( half the coefficient of the r- term )² to both sides

r² + 2(6)r + 36 = - 35 + 36

(r + 6)² = 1 ← take the square root of both sides )

r + 6 = ± 1 ( subtract 6 from both sides )

r = - 6 ± 1, thus

r = - 6 - 1 = - 7 or r = - 6 + 1 = - 5

7 0
3 years ago
X + 2 = 5x + 26<br><br> Please help
kkurt [141]
x+2=5x+26

Move all the x's to one side of the equation. This is a step necessary to solve this equation.

Subtract both sides by x.

x+2-x=5x+26-x
2=4x+26

Flip equation. We always want to have the variable written on the left side.

4x+26=2

Subtract both sides by 26.

4x+26-26=2-26
4x=-24

Divide both sides by 4 to finish this off.

x=-6

That's your answer. Have an awesome day! :)
7 0
3 years ago
How do you solve this equation?
Travka [436]
Exponentail thingies

easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0

now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero

5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1


5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4

x=log₅1 and/or log₅4







second quesiton

same thing

1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero

2^x-8=9
2^x=8
x=3

2^x-2=0
2^x=2
x=1

x=3 or 1







first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3


7 0
3 years ago
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