The answer to the equation is the second option.
Answer:
real
Step-by-step explanation:
300000
for all 
in [-3, 0], so 
is non-decreasing over this interval, and in particular we know right away that its minimum value must occur at 
.
From the plot, it's clear that on [-3, 0] we have 
. So
for some constant 
. Given that 
, we find that
so that on [-3, 0] we have
and
Answer:
there can only be one possibility for a triangle when given the lengths of all the sides but for a quadrilateral the measure of the angles could differ depending on the person building the,. this is because triangles are more stable than quadrilaterals meaning that their side lengths follow a lot more rules than quadrilaterals do, for example the length of the side lengths can indicate whether or not that triangle is an acute, obtuse, or right triangle, and this is also evident by considering that you can use the SSS theorem to indicate two triangles are congruent, but for quadrilaterals you cant do that
Step-by-step explanation:
Answer:
x intercept: (3, 0), (7, 0)
y-intercept: (0, -21)
vertex : (5,4)
the graph points down
Step-by-step explanation:
f(x) = - (x - 3)(x - 7)
f(x) = - (x^2 - 7x - 3x + 21)
f(x) = - (x^2 - 10x + 21)
f(x) = -x^2 + 10x - 21
x-intercept when f(x) = 0 so
x - 3 = 0; x = 3
x - 7 = 0; x = 7
x intercept: (3, 0), (7, 0)
y-intercept when x = 0 so y = -21
y-intercept: (0, -21)
vertex:
x = -b/2a
x = -10/ 2(-1)
x = 5
plug in x = 5 into the equation to find y
y = -(5)^2 + 10(5) - 21
y = -25 + 50 - 21
y = 4
so vertex : (5,4)
Since a = - 1<0, the graph is going downward and has maximum
