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frosja888 [35]
3 years ago
10

What is the measure of angle C

Mathematics
1 answer:
vlabodo [156]3 years ago
8 0

Answer:

pls I can't see any diagram anywhere

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Find The derivative of:(cosx/1+sinx)^3​
forsale [732]

Answer:

-\frac{3 \cdot cos^2x}{(1+sinx)^3}

Step-by-step explanation:

y = (\frac{cosx}{1+sinx})^3\\\\\frac{dy}{dx} = 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{dy}{dx}(\frac{cosx}{1+sinx})                        [ y = x^n\  \  \ =>  \  \  \  \frac{dy}{dx} = b \cdot x^{n-1} \ ]

    = 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{(1+sin x(-sinx) - cosx(cosx)}{(1+sinx)^2}\\\\     [\ \frac{u}{v} = \frac{v \dcot u'- u \cdot v'}{v^2}\ ]

    = 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x-sin^2x- cos^2x}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x- (sin^2x+ cos^2x)}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x-1}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-1 \cdot(sin x+1)}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-1}{(1+sinx)}\\\\

   = -3 \cdot \frac{cos^2x}{(1+sinx)^3}

   

5 0
3 years ago
WHICH HAT HELP THANK YOU WHICH HAT HELP THANK YOU
Svetradugi [14.3K]

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52.38%

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P(991<X<997) = normalcdf(991,997,993,4) = 0.5328, therefore, about 52.38% of the bottles have volumes between 991 mL and 997 mL

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