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satela [25.4K]
3 years ago
10

Find an equation of a line through √3,1 / 2) parallel to the line:

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
8 0

Answer:

(a) x=\sqrt{3}

(b) y=\frac{1}{2}

(c) Answer of part a is equation of line x=\sqrt{3} which is parallel to y axis and in part by equation of line is y=\frac{1}{2} which is parallel to x axis

Step-by-step explanation:

We have given points are (\sqrt{3},\frac{1}{2})

(a) Equation of line is given x = -9

We have to find the equation of line parallel to x= -9 and passing through (\sqrt{3},\frac{1}{2})

x = -9 line is parallel to y axis and so slope will be infinite

Equation of line is given by y-y_1=m(x-x_1)

So y-\frac{1}{2}=\frac{1}{0}(x-\sqrt{3})

x=\sqrt{3}

(b) Equation of line is given y=-\sqrt{7}

This line is parallel to x axis so slope will be zero

So equation of line will be y-\frac{1}{2}=0(x-\sqrt{3})

y=\frac{1}{2}

(c) Answer of part a is equation of line x=\sqrt{3} which is parallel to y axis and in part by equation of line is y=\frac{1}{2} which is parallel to x axis

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Evaluate this exponential expression.
Levart [38]

Answer:

(-27)^\dfrac{2}{3} = 9

Step-by-step explanation:

Given that,

Asn expression : (-27)^\dfrac{2}{3}

We need to evaluate the above expression.

We know that, (-3)^3=-27

So,

(-27)^\dfrac{2}{3}=(-3)^{3\times \dfrac{2}{3}}

or

=(-3)^2\\\\=-3\times -3\\\\=9

So, the value of (-27)^\dfrac{2}{3} is 9. Hence, the correct option is (b).

8 0
3 years ago
1. Which point on the axis satisfies the inequality y
grigory [225]

Answer:

1) Point (1,0) -----> see the attached figure N 1

2) The value of x is 4

3) I quadrant

4) (1,1)

5)  y>-5x+3

Step-by-step explanation:

Part 1)

we know that

If the point satisfy the inequality

then

the point must be included in the shaded area

The point (1,0) is included in the shaded area

Part 2)

we have

x-2y\geq 4

see the attached figure N 2

we know that

The value for x on the boundary line and the x axis is equal to the x-intercept of the line x-2y= 4

For y=0

Find the value of x

x-2(0)= 4  

x=4

The solution is x=4

Part 3)

we have

x\geq 0 -----> inequality A

The solution of the inequality A is in the first and fourth quadrant

y\geq 0 -----> inequality B

The solution of the inequality B is in the first and second quadrant

so

the solution of the inequality A and the inequality B is the first quadrant

Part 4) Which ordered pair is a solution of the inequality?

we have

y\geq 4x-5

we know that

If a ordered pair is a solution  of the inequality

then

the ordered pair must be satisfy the inequality

we're going to verify all the cases

<u>case A)</u> point (3,4)

Substitute the value of x and y in the inequality

x=3,y=4

4\geq 4(3)-5

4\geq 7 ------> is not true

therefore

the point (3,4) is not a solution of the inequality

<u>case B)</u> point (2,1)

Substitute the value of x and y in the inequality

x=2,y=1

1\geq 4(2)-5

1\geq 3 ------> is not true

therefore

the point  (2,1) is not a solution of the inequality

<u>case C)</u> point (3,0)

Substitute the value of x and y in the inequality

x=3,y=0

0\geq 4(3)-5

0\geq 7 ------> is not true

therefore

the point  (3,0) is not a solution of the inequality

<u>case D)</u> point (1,1)

Substitute the value of x and y in the inequality

x=1,y=1

1\geq 4(1)-5

1\geq -1 ------> is true

therefore

the point  (1,1) is  a solution of the inequality

Part 5) Write an inequality to match the graph

we know that

The equation of the line has a negative slope

The y-intercept is the point (3,0)

The x-intercept is a positive number

The solution is the shaded area above the dashed line

so

the equation of the line is y=-5x+3

The inequality is  y>-5x+3

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━━━━━━━☆☆━━━━━━━

▹ Answer

<em>16q + 4</em>

▹ Step-by-Step Explanation

10q + 5 + 6q - 1

10q + 6q + 5 - 1

16q + 4

Hope this helps!

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Brainliest is greatly appreciated!

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A newsletter publisher believes that less than 49% of their readers own a laptop. For marketing purposes, a potential advertiser
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Answer:

The answer is "At the 0,10 level, there should be enough proof that the percentage is below 49%"

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Null and alternative hypothesis:

H_0 :P \geq 0.49\\\\H_1:P

Significance level: \alpha = 0.10

It is decided that the null hypothesis at the defined meaning level is rejected.

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