This is a question that can be solved with Pythagorean Theorem since it is a right triangle. The longest side, 29, is the hypotenuse and the sides 21 and x are the legs. So, the Pythagorean Theorem states,

$c^{2}= a^{2}+ b^{2}$

Where,

c is the Hypotenuse, a and b are the legs. Putting the respective values gives us,

$(29)^{2}= (21)^{2} +x^{2} \\841=441+x^{2} \\400=x^{2} \\20=x$

So, 20 is the side length of x.

ANSWER: 20

5 0

2 years ago

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Kendra found two worms in the yard and measured them with a ruler. One worm was 7 2/3 inches long. The other worm was 2 1/6 inch

Black_prince [1.1K]

Answer:

5½ inches

Step-by-step explanation:

7⅔ - 2 1/6 = 7 4/6 - 2 1/6 = 5 3/6 = 5½

3 0

2 years ago

Find the value of x in each case. Give reasons to justify your solutions! e L, M ∈ KN

Greeley [361]

Answer:

X=36

Step-by-step explanation:

3x+72=180

3x=180-72

3x=108

x=36

8 0

2 years ago

What is the factored form of 64g^3+8

vivado [14]

$\bf \textit{difference and sum of cubes}
\\\\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 
\\\\
a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3\\\\
-------------------------------\\\\
64g^3+8\implies 4^3g^3+8\implies (4g)^3+2^3
\\\\\\
(4g+2)[(4g)^2-(4g)(2)+2^2]\implies (4g+2)[(4^2g^2)-8g+4]
\\\\\\
(4g+2)(16g^2-8g+4)$

3 0

2 years ago