What are the like terms in the expression below? 3x + 8 + 3y + 8x

Find the volume of this cylinder.

Lina20 [59]

Answer:

The answer is 3418.1 ft rounded to the nearest tenth.

Step-by-step explanation:

The total volume of the cylinder can be defined by the Area of circular base * Perpendicular height.

The area of the circular base can be calculated as

$\pi \times {r}^{2}$

where r is the radius of the circular base, which is 8 ft.

The area of the circular base is

$\pi \times {8}^{2} = 64\pi$

We also know the height of the cylinder is 17 ft.

Hence, the volume of the cylinder is

$64\pi \times 17 = 1088\pi = 3418.0528...$

This will be rounded up to 3418.1 with the nearest tenth

8 0

2 years ago

For question 3, is it right though? Thankss

pishuonlain [190]

Yes it is correct, 7/12 is the equivalent to C. 7 divided by 12

8 0

2 years ago

What’s the Coefficient of a2?

hjlf

The coefficient would be 2.

3 0

2 years ago

The volume of a cone with a radius of 7 cm is 147 cubic centimeters. Which expression can be used to find h, the height ofthe co

spayn [35]

The choices are not attached but we can solve the problem from the given information

Answer:

The expression can be used to find h is $h=\frac{3V}{\pi r^{2}}$

The height of the cone is $\frac{9}{\pi }$ cm

Step-by-step explanation:

The formula of the volume of the cone is V = $\frac{1}{3}$ π r² h, where

r is the radius of its base
h is the height of it

Let us find the height of the cone from the formula of its volume

∵ V = $\frac{1}{3}$ π r² h

- Multiply both sides by 3

∴ 3 V = π r² h

- Divide both sides by π r²

∴ $\frac{3V}{\pi r^{2}}=h$

- Switch the two sides

∴ $h=\frac{3V}{\pi r^{2}}$

The expression can be used to find h is $h=\frac{3V}{\pi r^{2}}$

∵ The radius of the cone is 7 cm

∴ r = 7

∵ The volume of the cone is 147 cm³

∴ V = 147

- Substitute them in the expression of the height to find it

∵ $h=\frac{3(147)}{\pi (7)^{2}}$

∴ h = $\frac{9}{\pi }$ cm

The height of the cone is $\frac{9}{\pi }$ cm

4 0

3 years ago

Which equation is an identity?

Sav [38]

Answer:

Equation 3

Step-by-step explanation:

An identity is, simply put, an equation that is always true. 1 = 1, 2 = 2, and x = x are all examples of identities, as there's no case in which 1 ≠ 1, 2 ≠ 2, and x ≠ x. Essentially, if we can manipulate and equation so that we end up with the same value on either side, we've found an identity. Let's run through and try to solve each of these equations to see which one fulfills that condition:

8 - (6v + 7) = -6v - 1

8 - 6v - 7 = -6v - 1

1 - 6v = -6v - 1

1 = -1

This is clearly untrue. Moving on to the next equation:

5y + 5 = 5y - 6

5 = -6

Untrue again. Solving the third:

3w + 8 - w = 4w - 2(w - 4)

2w + 8 = 4w - 2w + 8

2w + 8 = 2w + 8

If we created a new variable z = 2w + 8, we could rewrite this equation as

z = z, which is always true. We can stop here, as we've now found that equation 3 is an identity.

4 0

2 years ago

What are the like terms in the expressionbelow?3x + 8 + 3y + 8x​

What are the like terms in the expressionbelow?3x + 8 + 3y + 8x