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sergeinik [125]
3 years ago
6

If rhodium cost $6,050 per ounce how much does it cost per gram?​

Mathematics
1 answer:
Juliette [100K]3 years ago
5 0

Answer:  With such a limited supply, rhodium doesn't come cheap. It is the most expensive of all precious metals, currently trading at $2,725 an ounce. (To give you a better idea of its cost, that's over twice as expensive as gold and 154 times more than silver.)

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3 years ago
Prove it. this question is from trigonometry ​
konstantin123 [22]

Answer:

See below for step-by-step proof.

Step-by-step explanation:

\textsf{Given expression}:

\cos^6 \theta+\sin^6 \theta

\textsf{Apply exponent rule} \quad a^{bc}=(a^b)^c:

\implies (\cos^2 \theta)^3+(\sin^2 \theta)^3

\textsf{Use the identity}\quad a^3+b^3=(a+b)^3-3ab(a+b):

\implies (\cos^2 \theta+\sin^2 \theta)^3-3 \cos^2 \theta\sin^2 \theta (\cos^2 \theta+\sin^2 \theta)

\textsf{Use the identity}\quad \sin^2 \theta + \cos^2 \theta=1:

\implies (1)^3-3 \cos^2 \theta\sin^2 \theta (1)

\implies 1-3 \cos^2 \theta\sin^2 \theta

\implies 1-3 (\cos \theta\sin \theta)^2

\textsf{Use the identity}\quad \sin 2 \theta=2 \sin \theta \cos \theta \implies \dfrac{1}{2}\sin 2 \theta= \sin \theta \cos \theta:

\implies 1-3 \left( \dfrac{1}{2}\sin 2 \theta\right)^2

\implies 1-\dfrac{3}{4} \sin^2 2 \theta

\textsf{Use the identity}\quad \sin^2 2\theta + \cos^2 2\theta=1 \implies \sin^2 2\theta=1-\cos^2 2\theta

\implies 1-\dfrac{3}{4} \left(1-\cos^2 2 \theta\right)

\implies 1-\dfrac{3}{4} +\dfrac{3}{4}\cos^2 2 \theta

\implies \dfrac{1}{4} +\dfrac{3}{4}\cos^2 2 \theta

\textsf{Factor out }\dfrac{1}{4}:

\implies \dfrac{1}{4}\left(1+3\cos^2 2 \theta\right)

\textsf{Use the identity}\quad \cos (4 \theta)=2 \cos^2 2\theta - 1 \implies \cos^2 2 \theta=\dfrac{1}{2}\cos 4 \theta+\dfrac{1}{2}:

\implies \dfrac{1}{4}\left(1+3\left(\dfrac{1}{2}\cos 4 \theta+\dfrac{1}{2}\right)\right)

\implies \dfrac{1}{4}\left(1+\dfrac{3}{2}\cos 4 \theta+\dfrac{3}{2}\right)

\implies \dfrac{1}{4}\left(\dfrac{5}{2}+\dfrac{3}{2}\cos 4 \theta\right)

\implies \dfrac{1}{4} \cdot \dfrac{1}{2}\left(5+3\cos 4 \theta\right)

\implies \dfrac{1}{8}\left(5+3\cos 4 \theta\right)

6 0
2 years ago
What is the value of g^-1(9)
mars1129 [50]
Hi there!

• g(x) = 6x - 3

Then,
if g(x) = y :-

y = 6x - 3

⇒6x = y + 3

⇒x = \dfrac{\text{y} + 3}{6}

According to th' question :-

g⁻¹(x) = \dfrac{\text{x} + 3}{6}

g⁻¹(9) = \dfrac{9 + 3}{6}

g⁻¹(9) = \dfrac{12}{6}

g⁻¹(9) = 2

Hence,
The required answer is g⁻¹(9) = 2

~ Hope it helps!
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Answer:

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Step-by-step explanation:

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4 years ago
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Answer:

33 seconds i believe, im pretty sure its all about multiplication

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