30 lawnmowers in 20 hours. You can use proportion to solve this. 8/12 times 30 equals 20 hours. You know what I mean with proportion, right?
12 lawnmowers in 8 hours
30 lawnmowers in ? hours
(30 * 8)/ 12= 20
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~Rania
Answer:
b = 2 or b = 7
Step-by-step explanation:
b/(b-7) - 2/b = 7/ (b-7)
b * b - 2(b - 7) = 7 * b
b^2 - 2b + 14 = 7b
b^2 - 9b + 14 = 0
(b - 2)(b - 7) = 0
b - 2 = 0; b = 2
b - 7 = 0; b = 7
Answer
b = 2 or b = 7
Answer:
To get the highest scores, one needs to answer 4 computational problems and 8 graphical problems.
Step-by-step explanation:
Let x be the required number of computational problems one can answer
And y be the number of graphical problems one can answer.
- One cannot answer more than 12 questions in total
x + y ≤ 12
- Computational problems take 2 mins to answer and graphical problems take 4 mins to answer and there is a maximum of 40 mins for the quiz
2x + 4y ≤ 40
- Then finally, there 6 points associated with a computational problem and 10 points associated with a graphical problem and we want to maximize the number of points obtained from the test.
P(x,y) = 6x + 10y
So, the problem looks more like a linear programming problem to maximize
P(x,y) = 6x + 10y
subject to the constraints
x + y ≤ 12
2x + 4y ≤ 40
solving the constraint equations using the maximum values of the inequalities
x + y = 12
2x + 4y = 40
From the first eqn, x = 12 - y
Substituting into the second wan
2(12 - y) + 4y = 40
24 - 2y + 4y = 40
2y = 16
y = 8
x = 12 - y = 12 - 8 = 4
So, the solution of the equation of constraints, or even the graph of both constraint equation is
x = 4, y = 8
These represents the number of computational and graphical problems to maximally satisfy the constraints and maximize the required number of points.
Hope this Helps!!!