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Margarita [4]
3 years ago
11

A group of 16 friends visited an amusement park. When they arrived, 3/4 of the friends wanted to ride the fastest roller coaster

first. How many friends (f) wanted to ride?
Mathematics
2 answers:
vesna_86 [32]3 years ago
6 0
12 friends wanted to ride the roller coaster because 1/4 of 16 is 4 and 3/4 of 16 is 12
SashulF [63]3 years ago
5 0
Hi there!

12 friends wanted to ride.

For this you multiply:

16 x 3/4 = 12.

Hope this helps :)
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Yes and No.  

Step-by-step explanation:

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4 years ago
Two cyclists, 112 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other, and the
Iteru [2.4K]

Answer:

Speed of a= 21 miles/hr

r = Speed of b= 7 miles/hr

Speed of a = 3r

Step-by-step explanation:

The cyclist are 112 miles apart

Time traveled by two = 4 hours

Speed of a = 3 * speed of b

If a cylcles 3 times More than b, then a will cover 3*distance of b

But speed = distance/time

Time = 4hours

Total distance=112

a = 3b

3b + b = 112

4b = 112

b = 112/4

b = 28 miles

a = 3b

a = 3*28

a = 84 Miles

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Speed of b = 28miles/4 hours

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5 0
4 years ago
the sum of the first n terms of a sequence is 20 - 10 / 2 ^ n - 1 find the sum of the first five terms​
Travka [436]

Answer:

S_5=\dfrac{170}{9}

Step-by-step explanation:

Given that,

The sum of first n term of a sequence isS_n=20-\dfrac{10}{2n-1}

We need to find the sum of the first 5 terms.

Put n = 5,

S_5=20-\dfrac{10}{2(5)-1}\\\\=20-\dfrac{10}{10-1}\\\\=20-\dfrac{10}{9}\\\\=\dfrac{170}{9}

So, the sum of first 5 terms is equal to \dfrac{170}{9}.

6 0
3 years ago
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