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Paul [167]
3 years ago
14

Someones question was deleted: Rathan thinks all factors of even numbers are even. Which explains whether Rathan is correct? Ans

wer: C. He is incorrect because the product of an even number and an odd number is even. The product of even numbers isn't always going to even, but the product of an even number and an odd number will be. Even times odd always equals even examples: 2 x 3 = 6 8 x 7 = 56 17 x 40 = 680
Mathematics
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

as mentioned in the question

C as the answer.

Step-by-step explanation:

He is incorrect because the product of an even number and an odd number is even. The product of even numbers isn't always going to even, but the product of an even number and an odd number will be. Even times odd always equals even examples: 2 x 3 = 6 8 x 7 = 56 17 x 40 = 680

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Answer:

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Second option: 2x^2=6x-5

Fourth option: -x^2-10x=34

Step-by-step explanation:

Rewrite each equation in the form ax^2+bx+c=0 and then use the Discriminant formula for each equation. This is:

D=b^2-4ac

1) For 3x^2-5x=-8:

 3x^2-5x+8=0

Then:

D=(-5)^2-4(3)(8)=-71

Since D this equation has no real solutions, but has two complex solutions.

2) For 2x^2=6x-5:

 2x^2-6x+5=0

Then:

D=(-6)^2-4(2)(5)=-4

Since D this equation has no real solutions, but has two complex solutions.

3) For 12x=9x^2+4:

 9x^2-12x+4=0

Then:

D=(-12)^2-4(9)(4)=0

Since D=0 this equation has one real solution.

4) For -x^2-10x=34:

 -x^2-10x-34=0

Then:

D=(-10)^2-4(-1)(-34)=-36

Since D, this equation has no real solutions, but has two complex solutions.

3 0
3 years ago
Can you help me i got two wrong if I get one wrong I will have a falling grade
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Answer:

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Step-by-step explanation:

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Work:

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Step-by-step explanation:

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