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posledela
3 years ago
12

PLZ HELP!!!

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
7 0

The range of scores in Ms. Biren’s class is greater than the range of scores in Mr. Hayes’s class.

This would mean there was likely more variety (variability) in Ms. Biren's class than Mr. Hayes's, which is what we know.

Ilya [14]3 years ago
5 0

Answer:

C: The range of scores in Ms. Biren’s class is greater than the range of scores in Mr. Hayes’s class.

Step-by-step explanation:

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stiv31 [10]

Answer:

Divide both sides by 4

Step-by-step explanation:

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2 Construct a rational function that will help solve the problem. Then, use a calculator to answer the question.
vaieri [72.5K]

Answer:

<u><em>Dimension of box:-</em></u>

Side of square base = 10 in

Height of box = 5 in

Minimum Surface area, S = 300 in²

Step-by-step explanation:

An open box with a square base is to have a volume of 500 cubic inches.

Let side of the base be x and height of the box is y

Volume of box = area of base × height

                 500=x^2y

Therefore, y=\dfrac{500}{x^2}

It is open box. The surface area of box, S .

S=x^2+4xy

Put  y=\dfrac{500}{x^2}

S(x)=x^2+\dfrac{2000}{x}

This would be rational function of surface area.

For maximum/minimum to differentiate S(x)

S'(x)=2x-\dfrac{2000}{x^2}

For critical point, S'(x)=0

2x-\dfrac{2000}{x^2}=0

x^3=1000

x=10

Put x = 10 into y=\dfrac{500}{x^2}

y = 5

Double derivative of S(x)

S''(x)=2+\dfrac{4000}{x^3} at x = 10

S''(10) > 0

Therefore, Surface is minimum at x = 10 inches

Minimum Surface area, S = 300 in²

7 0
3 years ago
Find the height of the figure below if the volume is 480.66 cm^3.
salantis [7]

V=\pi r^{2}h\\ 480.66=\pi  6^{2} h\\first, divide both sides by \pi:\\153=6^{2}h\\153=36h\\divide both sides by 36:\\4.25=h

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3 years ago
ΔABC is similar to ΔDEF. The length of segment AC is 12 cm. The length of segment BC is 18 cm. The length of segment DF is 10 cm
SCORPION-xisa [38]

Answer:

It's 15

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Step-by-step explanation:

5 0
2 years ago
Please help and show work
GrogVix [38]

Answer:

Step-by-step explanation:

This is a right triangle trig problem. The base of the right triangle is the distance that Donna if from the flagpole; the flagpole is the side opposite the reference angle which was given as 26, and we are looking for the height of the flagpole, h. The trig ratio that uses the side opposite over the side adjacent is the tangent ratio, specifically:

tan26=\frac{h}{123} and

123tan(26) = h so

h = 60.0 rounded to the nearest tenth. But that is only the height from her line of vision and up, not the whole height. In order to find the whole height, we have to add in her height up to her line of vision which is 5.3 feet. Therefore, the height of the flagpole is

60.0 + 5.3 = 65.3 feet.

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