Answer: Explanation: 102=2⋅51. i102=(i2)51=(−1)51=−1.
Step-by-step explanation:
Answer:
Step-by-step explanation:
I can't see the screenshot
so like yeah
Answer:
you have 9 yes and 3 no. so 3/9=1/3=.333
Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
