All categories

3 years ago

A scale on a hiking map shows that 333 inches represents 1.251.251, point, 25 miles.

Mathematics

2 answers:

const2013 [10]3 years ago

7 0

Answer:

24 inches

Step-by-step explanation:

The 10 mile distance of interest is 8 times the 1.25 mile distance that corresponds to 3 inches. Hence 10 miles will correspond to 8 times 3 inches, or 24 inches.

Alecsey [184]3 years ago

7 0

ANSWER

7.5

----------------------------

How i got it?

We can use our scale 3:10 and the actual distance of 25 km to find the number of centimeters.

If the kilometers are 2.5 times as long, then we also need to multiply the centimeters by 2.5

3 x 2.5 = 7.5

The number of centimeters on the map that represents an actual distance of 25 kilometers is 7.5, centimeters.

You might be interested in

What is the equation of the line in the graph

earnstyle [38]

b = - 4

slope m = (0 + 4)/(4 - 0) = 4/4 = 1

equation

y = x - 4

7 0

3 years ago

Please help me with this math problem

dedylja [7]

$7 - 5 \times 1 + 3 \times 7 = 2 + 21 = 23$

7 0

3 years ago

Read 2 more answers

What is the percent of decrease from 40 to 24?

dem82 [27]

Answer:

37.5 percent !!

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which is the graph of y = 2(x - 3)^2+2

makvit [3.9K]

go to demos. com press graphing calculator then type it in

5 0

3 years ago

Find side lengths C and H

Nuetrik [128]

Answer:

$\displaystyle c=\frac{2\sqrt{3}}{3}\\\\\displaystyle h=7\sqrt{2}\\$

Step-by-step explanation:

Right Triangles

A right triangle can be identified by the fact it has an internal angle of 90°. In a right triangle, the trigonometric ratios stand.

Let's consider the triangle to the left. We need to calculate side c, one of the legs of the triangle. We can use the angle adjacent to it (60°) or the angle opposite to it (30°) with the appropriate trigonometric ratio.

We'll use the adjacent angle, and

$\displaystyle tan60^o=\frac{2}{c}$

Solving for c

$\displaystyle c=\frac{2}{tan60^o}=\frac{2}{\sqrt{3}}$

Rationalizing

$\displaystyle c=\frac{2}{\sqrt{3}}\cdot \frac{\sqrt{3}}{\sqrt{3}}=\frac{2\sqrt{3}}{3}$

Now for the triangle to the right. The side h is the hypotenuse. Again, any of the two angles can be used (though they are equal, for it's an isosceles triangle). For any of them it is true that

$\displaystyle sin45^o=\frac{7}{h}$

Solving for h

$\displaystyle h=\frac{7}{sin45^o}=\frac{7}{\frac{\sqrt{2}}{2}}=\frac{14}{\sqrt{2}}$

Rationalizing

$\displaystyle h=\frac{14}{\sqrt{2}}\cdot \frac{\sqrt{2}}{\sqrt{2}}=\frac{14\sqrt{2}}{2}=7\sqrt{2}$

3 0

4 years ago