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Aleks04 [339]
3 years ago
12

Please help I’ll give brainliest

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
8 0

Answer:

B

Step-by-step explanation:  6 21  9 45

49 × 17 + 49 × 3

49 × (17 + 3)

49 × 20

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Find all the square roots of x2 ≡ 53 (mod 77)
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Answer:

x=\pm\sqrt{77n+53}

Step-by-step explanation:

We have been given an equivalence equation x^2\equiv 53\text{ (mod } 77). We are asked to find all the square root of the given equivalence equation.

Upon converting our given equivalence equation into an equation, we will get:

x^2-53=77n

Add 53 on both sides:

x^2-53+53=77n+53

x^2=77n+53

Take square root of both sides:

x=\pm\sqrt{77n+53}

Therefore, the square root for our given equation would be x=\pm\sqrt{77n+53}.

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castortr0y [4]
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