Answer:
1. C. Yes, because a sum of cubes can be factored
2a. false
2b. false
2c. true
2d. false (based on what is written in the equation; refer to step-by-step)
Step-by-step explanation:
1. Both 3 and 8 can be cubed, which is why x^3+8 can be factored (x+2)(x^2-2x+4)
2a. a^2-b^2 can be factored by the perfect square rule, so it should be (a-b)^2
2b. both terms are perfect squares, so you can factor, making it (a+b)(a-b)
2c. You can factor using the perfect square rule, making it (a+b)^2
2d. Most of what is in the equation is true, yet the correct solution would be (a-b)(a^2+ab+b^2)
Answer:
1.4
Step-by-step explanation:
Sample size: 3
Lowest value: 2.89
Highest value: 4.29
Range: 1.4
formula for calculating the range:
Range = maximum(x_i) - minimum(x_i)
where x_i represents the set of values.
Answer:
- <u>3 </u><u>and</u><u> 17</u> are required integers
Step-by-step explanation:
- Let one integer be x
- And other integer be y
x = 4y + 5
xy = 51
<u>According to </u><u>question </u><u>:</u>
➞ (4y + 5)y = 51
➞ 4y² + 5y = 51
➞ 4y² + 5y - 51 = 0
➞ 4y² + 17y - 12y - 51 = 0
➞ y (4y + 17) - 3(4y + 17) = 0
➞ (y - 3)(4y - 17) = 0
➞ y - 3 = 0
➞ <u>y = 3</u>
Hence,
➞ <u>y = 3</u>
➞ x = 4y + 5
➞ x = 4 (3) + 5
➞ x = 12 + 5
➞<u> </u><u>x = 17</u>
∴ The required integers are <u>3 and 17</u>
