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Aleksandr [31]
3 years ago
10

Find the distance from P to l. Line l contains points (-4,2) and (3,-5).Point P has coordinates (1,2).

Mathematics
1 answer:
Annette [7]3 years ago
7 0
Hello,

A=(-4,2)
B=(3,-5)
AB≡y-2=(x+4)(-7)/7==>y=-x-2

Slope of the perpendicular: 1

y-2=(x-1)1==>y=x+1 is the equation of the perpendicular.

Intersection: y=x+1 and y=-x-2 ==>(-3/2,-1/2)=Q

|PQ|²=(-1/2-2)²+(1+3/2)²=25/2
|PQ|=5√2/2≈3.5355339059....



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What are the domain and range of this relation? {(3, -9), (11,21), (121,34), (34,1), (23,45)}
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7 0
3 years ago
Will give brainliest lots of points A is the midpoint of LB,Lb =6x-17 and AB=2x+3
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5 0
3 years ago
Idk how to do this honestly
Anuta_ua [19.1K]
I get the answer being the same y= -1/2x +

Because b in intercept form is "0"

I used
m=y2-y1/x2-x1
M=-3-2/6-4
M=-5/10
M=-1/2

(-4,2)
Y=mx+b
2=-1/2 (-4)+b
B=2-(-1/2)(-4)
B=0

I did the same for second point
And got "0" for b


So my answer is get
Y=-1/2x


Unless someone else gets something else different.

I hope somewhat helps
8 0
3 years ago
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