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3 years ago

What are the Lines of symmetry?

Mathematics

1 answer:

TEA [102]3 years ago

7 0

Answer:

Step-by-step explanation:

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In year 13, the scientist will put tree wrap around tree 1 to protect it from the winter snow. The height of the tree wrap needs

Dominik [7]

Answer:

22 feet²

Step-by-step explanation:

We are given:

height of tree h = 45 inches

Circumference= πd × inches

But d = 22.2inches

Therefore area will be

Area = 22.2π × 45 inches²

Area = 3137 inches²

Let's convert from inches² to feet², we have:

1 foot = 12 inches.

Therefore,

1 square foot = 1foot × 1foot = 12inches×12inches

= 3137inches² / 144 inches²

= 22feet²

Note: I attached missing data which states that diameter at year 13 is 22.2inches

6 0

2 years ago

Read 2 more answers

The temperature is -6º C (degrees Celsius) in southern Chile. It is 20º colder (less) in Antarctica. What is the temperature in

krok68 [10]

If you start from a temperature of -6° C and you need to lower that temperature of 20 more degrees, you have to subtract:

$-6-20 = -26$

So, the temperature in Antarctica is -26° C

8 0

3 years ago

If the function f(x) = 4x^2 - x + 3, evaluate f(-2)

ira [324]

Answer: 21

Step-by-step explanation: f(-2) = 4· (-2)²-(-2) + 3 = 4·4 +2 +3

5 0

2 years ago

F(x) = 49 - x^2 (squared) f(5) = ___

Ostrovityanka [42]

Answer: 24

Step-by-step explanation:

we replace x with 5

f(5)=49-25=24

3 0

3 years ago

Help differentiate this

Arte-miy333 [17]

Answer:

$\displaystyle y' = 20x^3 + 6x^2 + 70x + 9$

General Formulas and Concepts:

Pre-Algebra

Distributive Property

Algebra I

Terms/Coefficients
Expand by FOIL
Functions
Function Notation

Calculus

Derivatives

Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = (x^3 + 7x - 1)(5x + 2)$

Step 2: Differentiate

Product Rule: $\displaystyle y' = \frac{d}{dx}[(x^3 + 7x - 1)](5x + 2) + (x^3 + 7x - 1)\frac{d}{dx}[(5x + 2)]$
Basic Power Rule [Derivative Property - Addition/Subtraction]: $\displaystyle y' = (3x^{3 - 1}+ 7x^{1 - 1} - 0)(5x + 2) + (x^3 + 7x - 1)(5x^{1 - 1} + 0)$
Simplify: $\displaystyle y' = (3x^2+ 7)(5x + 2) + 5(x^3 + 7x - 1)$
Expand: $\displaystyle y' = 15x^3 + 6x^2 + 35x + 14 + 5(x^3 + 7x - 1)$
[Distributive Property] Distribute 5: $\displaystyle y' = 15x^3 + 6x^2 + 35x + 14 + 5x^3 + 35x - 5$
Combine like terms: $\displaystyle y' = 20x^3 + 6x^2 + 70x + 9$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

4 0

2 years ago