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Sonbull [250]
3 years ago
14

What are the Lines of symmetry?

Mathematics
1 answer:
TEA [102]3 years ago
7 0

Answer:

Step-by-step explanation:

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Which of these properties is enough to prove that a given parallelogram is also a Rectangle?
lozanna [386]

we are supposed to find

Which of these properties is enough to prove that a given parallelogram is also a Rectangle?

As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.

The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.

In a parallelogram The opposite angles and opposite sides are always equal.

Hence the correct option is

The diagonals are congruent.

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Polynomial

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Tim and Luke start a lawn-mowing business and buy a lawnmower for $325. They plan to charge $25 to mow one lawn. Which inequalit
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lawnmower = 325 USD

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I have the first part but I don't know how to do the second part<br><br> h e l p
Debora [2.8K]

\bf \begin{array}{cll} \stackrel{ordinal}{position}&\stackrel{term}{value}\\ \cline{1-2} 1&12\\ 2&12+d\\ 3&12+d+d\\ 4&12+d+d+d\\ &12+3d \end{array}\qquad \implies ~\hfill \begin{array}{llll} \stackrel{\textit{4th term}}{12+3d}~~=~~\stackrel{\textit{4th value}}{3}\\\\ 3d=-9\implies d = \cfrac{-9}{3}\\\\ \stackrel{\textit{common difference}}{d = -3} \end{array}

well, we know the common difference is -3, to go from the 4th term to the 8th term, we need to add "d" 4 times or namely 3+4(-3), likewise to go from the 13th term to the 19th term we have to add "d" 6 times, or namely -24 + 6(-3).

\bf \stackrel{\textit{8th term}}{3+4(-3)}\implies 3-12\implies -9 \\\\\\ \stackrel{\textit{19th term}}{-24 + 6(-3)}\implies -24-18\implies -42

3 0
3 years ago
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