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Aleonysh [2.5K]
3 years ago
10

The graph of f (0) = -4 cos 0 is shown below. The range of this function is

Mathematics
1 answer:
Anika [276]3 years ago
5 0

Answer:

-4 ≤ f (\theta) ≤ 4

Step-by-step explanation:

The range of a function is the allowed y-values of the function.

We can simply look at the periodic function below and see that the y-value ranges from a negative 4 to a positive 4. It oscillates betwen -4 and 4. That is the range.

We can say -4 ≤ f (\theta) ≤ 4

Last answer choice is right.

*** <u>NOTE:</u> it is a type, not "0", rather "\theta"

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The interpolating polynomial is p(x) = 1-4x+3x^2.

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We want to find a quadratic polynomial p(x) such that p(-1)=8, p(1)=0 and p(2)=5. In order to do this let us write p(x) = a_0+a_1x+a_3x^2.

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\begin{cases} 8 = p(-1) &= a_0-a_1+a_2\\ 0 = p(1) &= a_0+a_1+a_2\\ 5 = p(2) &= a_0+2a_1+4a_2\end{cases}

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The augmented matrix of the system is

\begin{pmatrix}1 & -1 & 1 & 8\\ 1 & 1 & 1 & 0\\ 1 & 2 & 4 & 5\end{pmatrix}

In this matrix it is easy to eliminate the 1's of the first column and get

\begin{pmatrix} 1 & -1 & 1 & 8\\ 0 & 2 & 0 & -8\\ 0 & 3 & 3 & -3\end{pmatrix}

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p(x) = 1-4x+3x^2.

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