The top question is B. 30, because you have to set 7y-30 equal to 4y+60 since both lengths are the same.
We know that
In French club <span>there are
10 freshman
</span><span>12 sophomores
15 juniors
30 seniors
total of the members------> (10+12+15+30)=67
total </span> freshman-----> 10
so
<span>the probability that a freshman will be chosen=10/67
and
</span><span>the probability that a freshman will not be chosen=(67-10)/67
</span>the probability that a freshman will not be chosen=57/67---> 0.8507
0.8507= 85.07%
the answer is
the probability that a freshman will not be chosen is 85.07%
Answer:
A
Step-by-step explanation:
SA = πr² + πrs
r = 4.42
s = 2.61
SA = π(4.42)² + π(4.42)(2.61)
SA = 19.5364π + 11.5362π
SA = 61.34 + 36.22
SA = 97.56
The closest answer would be A.
Best of Luck!
Let p be
the population proportion. <span>
We have p=0.60, n=200 and we are asked to find
P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60
and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is
considered to be large and hence the sampling distribution of sample
proportion-^p will follow the z standard normal distribution. Hence this
sampling distribution will have the mean of all sample proportions- U^p = p =
0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] =
√[0.60*(1-0.60)/200] = √0.0012.
So, the probability that the sample proportion
is less than 0.58
= P(^p<0.58)
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0...
= P(z<-0.58)
= P(z<0) - P(-0.58<z<0)
= 0.5 - 0.2190
= 0.281
<span>So, there is 0.281 or 28.1% probability that the
sample proportion is less than 0.58. </span>
Answer:
18 21 24 24 =87 maybe trying to help
