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Arte-miy333 [17]
3 years ago
11

The probability density function f(x) of a random variable X that has a uniform distribution between a and b is:

Mathematics
2 answers:
timofeeve [1]3 years ago
8 0

Answer: -None of these choices.

PDF = 1/(b-a)

Step-by-step explanation:

The probability density function f(x) of a random variable X that has a uniform distribution between a and b is given by:

PDF = 1/(b-a) for X€[a,b]

otherwise zero.

Lunna [17]3 years ago
3 0

The probability density function (pdf) is;

f(x)=\frac{1}{b - a} for a ≤ x ≤ b.

while the mean is given as \frac{a + b}{2}

And the standard deviation given as \sqrt{\frac{(b - a)^{2} }{12} }

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Which one is proportional? Im a little confused lol
Kobotan [32]
Answer:

y = x + 4





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4 0
2 years ago
John made 357$ for 17 hours of work.
yanalaym [24]

Answer: 14 hours

Step-by-step explanation: First I found the unit rate of how much money per hour. So, 357 divided by 17 = 21. So know I know that she earns 21$ per hour. Then, I did 237 divided by 17 which would be 13 remainder 16. Since he only get paid if he works for a full hour, I think the answer would be 14.

3 0
2 years ago
Read 2 more answers
Can you guys help please im so confused
marissa [1.9K]

Answer:

a) see below

b) 40x20 meters

Step-by-step explanation:

Write down what you know:

- The area of the enclosure is length*width, so

A = x \cdot y

- The length of the fencing is 80 meters, so

2y + x = 80

Now we have to combine these two equations above, and get rid of y in the process.

First rewrite the second as:

y = 40 - \frac12 x

Then substitute for y in the first:

A = x (40 - \frac12 x) = 40x - \frac12x^2

b) To maximize A, find the zero of the first derivative:

A'(x) = 40 - x = 0 \implies x=40

So y = (80-40)/2 = 20 meters.

8 0
2 years ago
the area of a rectangle is 42.15 square meters. if the length is 21 meters, what is perimeters of the rectangle?
Vsevolod [243]

Answer:

perimeters of the rectangle=p=46.014 metres

Step-by-step explanation:

Given that:

Length (l) = 21 m

Area of rectangle(A) = 42.15 meter-square

Width (w)=?

Required data:

Perimater of Rectangle=p=?

Calculation:

As we know that Area of rectangle=A=l*w

Putting the value we get

42.15 m(square)=(21 m)*w

or w=42.15/21

or w=2.007 m

Now to find perimters of rectangle we know that

p=2(l + w) metres

putting the values

p=2(21+2.007) metres

p=2(23.007) metres

p=46.014 metres

7 0
3 years ago
Read 2 more answers
CAN YALL PLEASE WORK IT OUTTT <br><br> $18.79 + $2.11 + ‐$1.92 + $17.28
Dmitry [639]

Answer:

40.1

Step-by-step explanation:

Because the order of operations (Bodmas or Pedmas) tells you to add from left to right. So you would do 18.79 + 2.11 = 20.9, then you would do 20.90 + 1.92 (Add 0 at the end of 20.9) = 22.81. Then you will add 22.81 + 17.28 = 40.1. So your answer is 40.1. Hope this helps!

7 0
1 year ago
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