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4 years ago

What is the value of x?

Mathematics

1 answer:

Kryger [21]4 years ago

3 0

-1 because -3x+1=2 (4 total spaces) so,
2+1 is 3
you have life numbers and x values separate.
divide positive 3 by negative 3 to get -1.
check your answer by plugging it in
-1*-3 is 3
so - 3+1 world be 4 which is where the 2 is on the number line because it goes into negatives

answer is x= -1

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Given the graph, find the initial value of the domain [ ___, 2].

kifflom [539]

According to the graph given, and using it's concept, it is found that the initial value of the domain is of 0.

The domain of a function is the set that contains all possible input values.

In a graph, it is represented by the values of x, which is the horizontal axis.

In the graph given in this problem, the function is defined for x between 0 and 2, that is, the domain is [0,2], hence, the initial value of the domain is of 0.

To learn more about domain, you can take a look at brainly.com/question/25897115

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2 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

3 years ago

3/5+(-7/5)= can someone help me with this please

Tresset [83]

Answer:

$-\frac{4}{5}$

Step-by-step explanation:

Because both of the fractions have a common denominator they can be subracted without any other work.

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3 years ago

Identify the coefficient(s) in the algebraic expression shown below.

stich3 [128]

Answer:

3) 6 and 1

Step-by-step explanation:

A coefficient is always the number that is in the same term as the variable, and a variable always has a 1 in front of it

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3 years ago

This is a word problem where you have to create an equation and a solution to.

IrinaVladis [17]

You are asked to find the team score, so it is convenient to let a variable represent that value. Let's call it "s", for "score". The problem statement tells you
.. Michaela scored s/5 . . . . . one fifth of the team's points
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These scores together are (s/5 +s/10) and that amount is 42 points.
.. s/5 +s/10 = 42
.. s(2/10 +1/10) = 42 . . . . . factor out s
.. s(3/10) = 42 . . . . . . . . . . form the sum of the numbers in parentheses
.. s = 42*10/3 = 140 . . . . . multiply by the inverse of the coefficient of s

The team scored 140 points.

______
Michaela scored 140/5 = 28 points; Aleah scored 140/10 = 14 points.

3 0

4 years ago