<h3>
1.Area of the parallelogram= 288 square units</h3><h3>
2.Area of the parallelogram=45 
</h3><h3>
3.Area of the trapezoid = 34 square in.</h3><h3>
4.Area of the trapezoid = 8 square ft</h3><h3>
5.Area of the rhombus= 27 square cm</h3><h3>
6.Area of the rhombus= 108 square in</h3><h3>
7.The area of the desktop is = 1200 square in</h3><h3>
8.The area of the rhombus is =84 
</h3><h3>
9.Area of the trapezoid = 240 square ft</h3>
Step-by-step explanation:
1.
Base =16 ft and Height = 18 ft
Area of the parallelogram = base × height
=16× 18 square units
= 288 square units
2.
Base = 9 m and height = 5 m
Area of the parallelogram = base × height
=(9×5) 
=45 
3 .
Height = 4 in and parallel sides are 12 in and 5 in
Area of the trapezoid =
square in.
= 34 square in.
4.
Height = 2 ft and parallel sides are 2 ft and 6 ft
Area of the trapezoid =
square ft
= 8 square ft
5.
Diagonals are 6 cm and 9 cm.
Area of the rhombus 
square cm
= 27 square cm
6. Diagonals are 12 in and 18 in
Area of the rhombus 
square in
= 108 square in
7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in
The area of the desktop is = (30 × 40 ) square in
= 1200 square in
8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.
The area of the rhombus =

=84 
9.Given , the base of trapezoid are 24 ft and 16 ft and height is 12 ft
Area of the trapezoid =
=
square ft
= 240 square ft
Answer:
rs6657
Step-by-step explanation:
Remark
You'll see it a whole lot easier if you make a substitution so that it looks like something you have already seen
Solution
let y = x^2
x^4 = x^2 * x^2
x^4 = y * y
x^4 = y^2
Now the expression becomes
y^2 + 8 y - 9 = z
(y + 9)(y - 1) = z
Now put the x^2 back in.
(x^2 + 9) ( x^2 - 1) = z
x^2 - 1 becomes x + 1 and x - 1. At this level x^2 + 9 can't be factored.
Answer
(x^2 + 9) (x + 1)(x - 1)
Answer:
42 Dimes, 10 Nickels.
Step-by-step explanation:
Dimes are worth $0.10, nickels are worth $0.05.
If D = number of dimes, and N = number of nickels, then the following equations are true:
0.10D + 0.05N = 4.70
D + N = 52
Next, let's multiply the first equation by 10 so that we can subtract the second one from it.
D + 0.50N = 47
(-) D + N = 52
Subtracting the second equation from the first one gives:
-0.5N = -5
-0.5N/-0.5 = -5/-0.5
N = 10
Finally, substitute N in the original second equation to find D.
D + 10 = 52
D + 10 - 10 = 52 - 10
D = 42
Answer:
TQ = 10
Step-by-step explanation:
The diagonal divides the square into 2 right triangles with the diagonal being the hypotenuse.
Using Pythagoras' identity in triangle TPQ
TQ² = PQ² + PT²
TQ² = 10² + 10² = 100 + 100 = 200 ( take square root of both sides )
TQ =
=
=
×
= 10