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Olegator [25]
3 years ago
14

The area under a particular normal curve between 6 and 8 is 0.695. A normally distributed variable has the same mean and standar

d deviation as the parameters for this normal curve. What percentage of all possible observations of the variable lie between 6 and 8​?
Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0

Answer:

69.5%

Step-by-step explanation:

A feature of the normal distribution is that this is completely determined by its mean and standard deviation, therefore, if two normal curves have the same mean and standard deviation we can be sure that they are the same normal curve. Then, the probability of getting a value of the normally distributed variable between 6 and 8 is 0.695. In practice we can say that if we get a large sample of observations of the variable, then, the percentage of all possible observations of the variable that lie between 6 and 8 is 100(0.695)% = 69.5%.

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WILL GIVE BRAINLIEST<br>What is the value of a in the problem 4a-3=D<br>explain answer
mixas84 [53]
In this case, you aren't going to get an integer for the value of a, but you can rearrange the equation to equal a.

4a-3=D       add 3 to both sides
4a=D+3      divide both sides by 4
a=(D+3)/4   here's your answer
4 0
3 years ago
A shipment of 50,000 transistors arrives at a manufacturing plant. The quality control engineer at the plant obtains a random sa
Aleks04 [339]

Step-by-step explanation:

remember, the number of possible combinations to pick m out of n elements is C(n, m) = n!/(m! × (n-m)!)

50,000 transistors.

4% are defective, that means 4/100 = 1/25 of the whole.

so, the probability for one picked transistor to be defective is 1/25.

and the probability for it to work properly is then 1-1/25 = 24/25.

now, 500 picks are done.

to accept the shipment, 9 or less of these 500 picks must be defective.

the probability is then the sum of the probabilities to get

0 defective = (24/25)⁵⁰⁰

1 defective = (24/25)⁴⁹⁹×1/25 × C(500, 1)

= 24⁴⁹⁹/25⁵⁰⁰ × 500

2 defective = (24/25)⁴⁹⁸×1/25² × C(500, 2)

= 24⁴⁹⁸/25⁵⁰⁰ × 250×499

3 defective = 24⁴⁹⁷/25⁵⁰⁰ × C(500, 3) =

= 24⁴⁹⁷/25⁵⁰⁰ × 250×499×166

...

9 defective = 24⁴⁹¹/25⁵⁰⁰ × C(500, 9) =

= 24⁴⁹¹/25⁵⁰⁰ × 500×499×498×497×496×495×494×493×492×491 /

9×8×7×6×5×4×3×2 =

= 24⁴⁹¹/25⁵⁰⁰ × 50×499×166×71×31×55×494×493×41×491

best to use Excel or another form of spreadsheet to calculate all this and add it all up :

the probability that the engineer will accept the shipment is

0.004376634...

which makes sense, when you think about it, because 10 defect units in the 500 is only 2%. and since the whole shipment contains 4% defect units, it is highly unlikely that the random sample of 500 will pick so overwhelmingly the good pieces.

is the acceptance policy good ?

that completely depends on the circumstances.

what was the requirement about max. faulty rate in the first place ? if it was 2%, then the engineer's approach is basically sound.

it then further depends what are the costs resulting from a faulty unit ? that depends again on when the defect is usually found (still in manufacturing, or already out there at the customer site, or somewhere in between) and how critical the product containing such transistors is. e.g. recalls for products are extremely costly, while simply sorting the bad transistors out during the manufacturing process can be rather cheap. if there is a reliable and quick process to do so.

so, depending on repair, outage and even penalty costs it might be even advisable to have a harder limit during the sample test.

in other words - it depends on experience and the found distribution/probability curve, standard deviation, costs involved and other factors to define the best criteria for the sample test.

3 0
2 years ago
How many degrees is 1/4 of a circle?
irina1246 [14]
45 degrees is the answer to your problem

5 0
3 years ago
Read 2 more answers
Help me please. mad confused lol
SCORPION-xisa [38]

Answer:

P = 30 degrees, PQ = 6.93, PN = 8

Step-by-step explanation:

For the angle, just subtract the angles you already know from 180, so 180 - 90 - 60= P. P = 30 degrees.

For PQ, use tan60 = x/4, or 4tan(60), which equals 6.93.

For PN, use cos60 = 4/x, or 4/cos60, which equals 8.

Hopefully this helps- let me know if you have any questions!

7 0
3 years ago
Need urgent help in mathematics!! Will mark brainliest!!!!
Nataly [62]

₇P₅ is a permutation. you can find this setting in the statistics menu of your scientific calculator (i think).

If you don't have a scientific calculator, you can use the following formula:

nPr = \frac{n!}{(n - r)!}

₇P₅  = \frac{7!}{(7 - 5)!}

     = \frac{7}{2!}

     = \frac{7 * 6 * 5 * 4 * 3 * 2!}{2!}

     = 7 * 6 * 5 * 4 * 3

    = 2520

Answer: C

3 0
3 years ago
Read 2 more answers
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