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ser-zykov [4K]
3 years ago
12

The numbers on two consecutively numbered gym lockers have a sum of 141. What are the locker​ numbers?

Mathematics
2 answers:
lesantik [10]3 years ago
5 0

Answer:

70 and 71

Step-by-step explanation:

Consecutive means in a row

x is the first number

x+1 is the next number

x+ x+1 = 141

Combine like terms

2x+1 =141

Subtract 1 from each side

2x+1-1=141-1

2x= 140

Divide each side by 2

2x/2 =140/2

x = 70

The two lockers are 70,71

Grace [21]3 years ago
3 0

Answer:

70 and 71

Step-by-step explanation:

Let the two consecutive numbers be: x and x+1

x + x+1 = 141

2x + 1 = 141

2x = 140

x = 70

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The correct answer is  option C

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From the figure we can see two angles <ABC and <LMN,

<u>To find the correct option</u>

From figure we get,

m<ABC = 20°° and m<LMN = 70°

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Therefore <ABC and <LMN are complementary angles

The correct answer is option C

They are complementary angles

7 0
4 years ago
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What is 12/35 simplified
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In a 3-digit number, the hundreds digit is one more than the ones digit and the tens digit is twice the hundreds digit. If the s
MaRussiya [10]

Answer:

The mentioned number in the exercise is:

  • <u>362</u>

Step-by-step explanation:

To obtain the mentioned number in the exercise, first you must write the equations you can obtain with it.

If:

  • x = hundredths digit
  • y = tens digit
  • z = ones digit

We can write:

  1. x = z + 1 (the hundreds digit is one more than the ones digit).
  2. y = 2x (the tens digit is twice the hundreds digit).
  3. x + y + z = 11 (the sum of the digits is 11).

Taking into account these data, we can use the third equation and replace it to obtain the number and the value of each digit:

  • x + y + z = 11
  • (z + 1) + y + z = 11 (remember x = z + 1)
  • z + 1 + y + z = 11
  • z + z +y + 1 = 11 (we just ordered the equation)
  • 2z + y + 1 = 11 (z + z = 2z)
  • 2z + y = 11 - 1 (we passed the +1 to the other side of the equality to subtract)
  • 2z + y = 10
  • 2z + (2x) = 10 (remember y = 2x)
  • 2z + 2x = 10
  • 2z + 2(z + 1) = 10 (x = z + 1 again)
  • 2z + 2z + 2 = 10
  • 4z + 2 = 10
  • 4z = 10 - 2
  • 4z = 8
  • z = 8/4
  • <u>z = 2</u>

Now, we know z (the ones digit) is 2, we can use the first equation to obtain the value of x:

  • x = z + 1
  • x = 2 + 1
  • <u>x = 3</u>

And we'll use the second equation to obtain the value of y (the tens digit):

  • y = 2x
  • y = 2(3)
  • <u>y = 6</u>

Organizing the digits, we obtain the number:

  • Number = xyz
  • <u>Number = 362</u>

As you can see, <em><u>the obtained number is 362</u></em>.

8 0
3 years ago
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