In chickens, having feathers on legs is dominant to having featherless legs. In a population of 200 chickens, 128 have featherle ss legs. How many chickens are heterozygous for the "feathered leg" allele? Assume the population is in Hardy-Weinberg equilibrium.
1 answer:
Answer:
64
Explanation:
Since the population is in Hardy-Weinberg equilibrium and the equilibrium is defined by the equation
p² + 2pq + q²
where the frequency of the homozygous dominant allele F ( feathers on the leg ) = p²,
F of homozygous ( featherless legs) = q²
F of heterogyous ( carrier of featherless allele) = 2pq
F (q²) = 128/200 = 0.64
q = √0.64 = 0.8
and p + q = 1
p = 1 - 0.8 = 0.2
2pq = 2 × 0.2 × 0.8 = 0.32
number of chickens that are heterozgous for the feathered leg allele = 0.32 × 200 = 64
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