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3 years ago

I owe old is Mukesh ambani.

Mathematics

2 answers:

kupik [55]3 years ago

4 0

Mukesh Ambani is 61 years old

ololo11 [35]3 years ago

3 0

Answer:yes

Mukesh is 61 years old.

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What is the sum in simplest form? 5 3/4 + 2 1/2 A) 7 4/6 B) 7 2/3 C) 8 1/4

alina1380 [7]

Answer:

Step-by-step explanation:

5 3/4 + 2 1/2

Add the whole numbers first

5 + 2

Add the fractions next

3/4 + 1/2 = 3/4 + 2/4 = 5/4 = 1 and 1/4

The total is

7 + 1 1/4 = 8 1/4

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2 years ago

Find the value of x. 16 40° D (Round to the nearest tenth as needed.)

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Answer:

Step-by-step explanation:

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2 years ago

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irina1246 [14]

Answer:

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Step-by-step explanation:

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2 years ago

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Select the curve generated by the parametric equations. Indicate with an arrow the direction in which the curve is traced as t i

bixtya [17]

Answer:

length of the curve = 8

Step-by-step explanation:

Given parametric equations are x = t + sin(t) and y = cos(t) and given interval is

−π ≤ t ≤ π

Given data the arrow the direction in which the curve is traces means

the length of the curve of the given parametric equations.

The formula of length of the curve is

$\int\limits^a_b {\sqrt{\frac{(dx}{dt}) ^{2}+(\frac{dy}{dt}) ^2 } } \, dx$

Given limits values are −π ≤ t ≤ π

x = t + sin(t) ...….. (1)

y = cos(t).......(2)

differentiating equation (1) with respective to 'x'

$\frac{dx}{dt} = 1+cost$

differentiating equation (2) with respective to 'y'

$\frac{dy}{dt} = -sint$

The length of curve is

$\int\limits^\pi_\pi {\sqrt{(1+cost)^{2}+(-sint)^2 } } \, dt$

$\int\limits^\pi_\pi \, {\sqrt{(1+cost)^{2}+2cost+(sint)^2 } } \, dt$

on simplification , we get

here using sin^2(t) +cos^2(t) =1 and after simplification , we get

$\int\limits^\pi_\pi \, {\sqrt{(2+2cost } } \, dt$

$\sqrt{2} \int\limits^\pi_\pi \, {\sqrt{(1+1cost } } \, dt$

again using formula, 1+cost = 2cos^2(t/2)

$\sqrt{2} \int\limits^\pi _\pi {\sqrt{2cos^2\frac{t}{2} } } \, dt$

Taking common $\sqrt{2}$ we get ,

$\sqrt{2}\sqrt{2} \int\limits^\pi _\pi ( {\sqrt{cos^2\frac{t}{2} } } \, dt$

$2(\int\limits^\pi _\pi {cos\frac{t}{2} } \, dt$

$2(\frac{sin(\frac{t}{2} }{\frac{t}{2} } )^{\pi } _{-\pi }$

length of curve = $4(sin(\frac{\pi }{2} )- sin(\frac{-\pi }{2} ))$

length of the curve is = 4(1+1) = 8

conclusion:-

The arrow of the direction or the length of curve = 8

7 0

3 years ago

Find the radius of a circle on which a central angle measuring 2pie/3 radiance intercept in arc on the circle with an length of

frosja888 [35]

28 is the answer to ur question

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3 years ago