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anzhelika [568]
2 years ago
10

What substitution should be used to rewrite 6(x + 5)2 + 5(x + 5) -4 = 0 as a quadratic equation?

Mathematics
1 answer:
laiz [17]2 years ago
4 0

The substitution that should be used to rewrite the equation is u = x+5, the correct option is A.

<h3>What is a Quadratic Equation?</h3>

The polynomials of the 2nd degree are called Quadratic Equations.

It has a general form as ax² +bx+c=0

To rewrite the expression as a quadratic equation  

6(x+5)² + 5(x+5)-4 = 0

=6(x+5)(x+5)+5(x+5)-4

=6(x² + 5x + 5x + 25)+5(x+5)-4

=6(x²+10x+25) + 5(x+5) - 4 = 0

=6x² + 60x + 5x + 150 + 25 - 4 = 0

=6x² + 65x + 171 = 0

This is the quadratic equation of the form ax² +bx+c=0

but if directly it has to be written in this ax² +bx+c=0 form , it can be written by substituting u = (x + 5)

6(x+5)² + 5(x+5)-4 = 0

6u²+5u-4 = 0

Therefore, the substitution that should be used to rewrite the equation is u = x+5, the correct option is A.

To know more about Quadratic equations

brainly.com/question/2263981

#SPJ1

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