The probability that a 2 or 3 is rolled at least once is 0.14.
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Probability of not rolling a 2 or 3 in a single die roll of two dice</h3>
when a six die is rolled once there is 11/12 probability of not rolling 2 or 3.
rolling a six sided die two times, p(2 or 3)' = 11/12
rolling a six sided die four times, p(2 or 3)' = (11/12)² = 121/144
the probability that a 2 or 3 is rolled at least once is calculated as follows;
P = 1 - p(2 or 3)'
P = 1 - 121/144
P = 20/144
P = 0.14
Thus, the probability that a 2 or 3 is rolled at least once is 0.14.
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Answer:
0.0918 = 9.18% probability that a randomly selected male has a height > 180 cm.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 170cm and standard deviation of 7.5 cm.
This means that 
Find the probability that a randomly selected male has a height > 180 cm.
This is 1 subtracted by the pvalue of Z when X = 180. So



has a pvalue of 0.9082
1 - 0.9082 = 0.0918
0.0918 = 9.18% probability that a randomly selected male has a height > 180 cm.
(3+2.5+2.7)/3 = 8.2/3 = 2.733... or 2 11/15
Answer:
65
Step-by-step explanation:
520/8=65 so approximately 65 kids play soccer
What number is m and what number is n?