Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
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Add sides 6


Divide sides by 2


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The correct answer is (( B )) .
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Answer:
Step-by-step explanation:
the child takes 1/5.....the baby needs to take 1/5 of what the child takes
so 1/5 of 1/5....." of " in math, means multiply
1/5 * 1/5 = 1/25 of the amount <==
Answer:
Straight 180
Reflex 210
Right 90
Acute 75
Obtuse 135
Step-by-step explanation: