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2 years ago

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A six sided die is rolled 4 times. find the probability that a 2 or 3 is rolled at least once. round your answer to two decimal

places.

1 answer:

goblinko [34]2 years ago

4 0

The probability that a 2 or 3 is rolled at least once is 0.14.

<h3>Probability of not rolling a 2 or 3 in a single die roll of two dice</h3>

when a six die is rolled once there is 11/12 probability of not rolling 2 or 3.

rolling a six sided die two times, p(2 or 3)' = 11/12

rolling a six sided die four times, p(2 or 3)' = (11/12)² = 121/144

the probability that a 2 or 3 is rolled at least once is calculated as follows;

P = 1 - p(2 or 3)'

P = 1 - 121/144

P = 20/144

P = 0.14

Thus, the probability that a 2 or 3 is rolled at least once is 0.14.

Learn more about probability here: brainly.com/question/24756209

#SPJ4

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3 years ago

Tesfa is x years old. his father is 4 times as old as Tesfa. Her mother is 7 years younger than his father. If their three ages

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3 years ago

For which function is f(x) equal to f^1(x) ( answer choices in picture )

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Answer:

C. $f(x)=\frac{x+1}{x-1}$

Step-by-step explanation:

Let's find the inverse of each of the given options.

Option A:

$f(x)=\frac{x+6}{x-6}\\y=\frac{x+6}{x-6}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+6}{y-6}$

Rewrite in terms of 'y'. This gives,

$x(y-6)=y+6\\xy-6x=y+6\\xy-y=6x+6\\y=\frac{6x+6}{x-1}$

The given function $y=\frac{6x+6}{x-1}\ne y=\frac{x+6}{x-6}$

So, option A is incorrect.

Option B:

$f(x)=\frac{x+2}{x-2}\\y=\frac{x+2}{x-2}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+2}{y-2}$

Rewrite in terms of 'y'. This gives,

$x(y-2)=y+2\\xy-2x=y+2\\xy-y=2x+2\\y=\frac{2x+2}{x-1}$

The given function $y=\frac{2x+2}{x-1}\ne y=\frac{x+2}{x-2}$

So, option B is incorrect.

Option C:

$f(x)=\frac{x+1}{x-1}\\y=\frac{x+1}{x-1}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+1}{y-1}$

Rewrite in terms of 'y'. This gives,

$x(y-1)=y+1\\xy-x=y+1\\xy-y=x+1\\y=\frac{x+1}{x-1}$

The given function $y=\frac{x+1}{x-1}\ equals\ y=\frac{x+1}{x-1}$

So, option C is correct.

Option D:

$f(x)=\frac{x+5}{x-5}\\y=\frac{x+5}{x-5}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+5}{y-5}$

Rewrite in terms of 'y'. This gives,

$x(y-5)=y+5\\xy-5x=y+5\\xy-y=5x+5\\y=\frac{5x+5}{x-1}$

The given function $y=\frac{5x+5}{x-1}\ne y=\frac{x+6}{x-6}$

So, option D is incorrect.

Therefore, only option C is correct.

7 0

3 years ago

Please help!!!!!!!!!!!!!!!!!!!!!

sleet_krkn [62]

It would be c I think

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3 years ago