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3 years ago

10

Hi, can someone please solve this question a put it on a number line to help me out? 0

2 answers:

DENIUS [597]3 years ago

8 0

Answer:whats the question

Step-by-step explanation:

lara31 [8.8K]3 years ago

3 0

What’s the question?

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13 points plus brainliest to the correct answer!

TEA [102]

The equation of a straight line is given by:

y = mx + c

where m is the slope and c is the y-intercept.

From the given graph, the y-intercept is 1.

The slope of a straight line is given by:

$m= \frac{y_2-y_1}{x_2-x_1}$

Where $(x_1,y_1)$ and $(x_2,y_2)$ are two points on the line.

From the graph, (0, 1) and (14, 8) are two points on the line, thus:

$m= \frac{8-1}{14-0} = \frac{7}{14} = \frac{1}{2}$

Therefore, the equation representing the graph is $y= \frac{1}{2} x+1$

8 0

3 years ago

Read 2 more answers

If 3 pounds of chocolate cost $25.50 how many pounds can you buy for $42.50

MrMuchimi

To solve this, write a proportion of Pounds to Cost:
Pounds: 3 x
Cost: 25.50 42.50

Cross multiply 3 and 42.50, this gives you 127.5
Then, divide by 25.5
This gives you 5.
You can buy 5 pounds with $42.50

8 0

2 years ago

Read 2 more answers

Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

5 0

3 years ago

Help ???????????????????????

Likurg_2 [28]

Answer:

I dont remember how to do this but i wish you luck, try searching on khan academy for how to do this ;)

Step-by-step explanation:

5 0

3 years ago

Given<br> the<br> function<br> f(x)= 3(x-2)² + 5, what<br> is<br> f(-1)?

motikmotik

Answer:

32

Step-by-step explanation:

f(x)= 3(x-2)² + 5

Let x = -1

f(-1)= 3(-1-2)² + 5

Parentheses first

f(-1) = 3(-3)^2 +5

Exponents

f(-1)= 3*9 + 5

Multiply

f(-1) = 27+5

Add

f(-1) = 32

5 0

2 years ago

Read 2 more answers