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1 year ago

Two of the angles in a triangle measure 57º and 25°. What must be the measure of the

Mathematics

1 answer:

ira [324]1 year ago

5 0

The measure of the third angle in the triangle is 104 degrees

<h3>How to determine the measure of the third angles?</h3>

Let the three angles in the triangle be x, y and z.

Such that:

x = 51

y = 25

The sum of angles in a triangle is 180 degrees.

So, we have:

x + y + z = 180

Substitute known values

51 + 25 + z = 180

Evaluate the sum

76 + z = 180

Subtract 76 from both sides

z = 104

Hence, the measure of the third angle is 104 degrees

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I don't know how to solve this. How would I solve this? Thanks!!!!

Afina-wow [57]

Answer:

x = 11 units

Step-by-step explanation:

Area of triangle = (base + base 2) * h *1/2

so (7 + x )* 7 * 1/2 = 63

63 x 2 = 126

126 / 7 = 18

18-7 = x

x = 11

Check

(7+11)* 7 * 1/2

18* 7 = 126

126 x 0.5 = 63

CORRECT!

(p.s., tell me if wrong :P)

6 0

2 years ago

Seattle, wa and san francisco, ca lie on the same longitudinal line. san francisco is at 38° latitude and seattle is at 47° lati

Varvara68 [4.7K]

Step 1.

Calculate measure of angle α:

$47^o-38^o=9^o$

Step 2.

Calculate what fraction of the angle 360° is the angle α:

$\dfrac{9^o}{360^o}=\dfrac{1}{40}$

Step 3.

Calculate the circumference of the Earth (circle):

$C=2\pi r\to C=2\pi\cdot4000=8000\pi\ mi$

Step 4.

The length of arc is equal 1/40 of the circumference:

$\dfrac{1}{40}C=\dfrac{1}{40}\cdot8000\pi=200\pi\ mi$

$\pi\approx3.14\to\dfrac{1}{40}C\approx200\cdot3.14=628\ mi$

<h3>Answer: A) 628 miles</h3>

8 0

2 years ago

g Let G be a not necessarily abelian group with normal subgroups H and K such that H contains K (i.e., K ✂ G, H ✂ G, K ≤ H) and

allsm [11]

Answer:

Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, $[ab]_K$ is equal to $[ba]_K$ , thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.

Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, $[ab]_H = [ba]_H$ . Since a and b were generic elements of H, then H/G is abelian.