Literal equations are I'm pretty sure more straight forward while algebraic is complication and requires a lot of steps
Step-by-step explanation:
Part A: The temperature must be greater than -40, and lower than 140. -40 < T < 140
Part B: The graph is a number line between -40 and 140, with open circles at -40 and 140. The solutions are temperatures at which the gas will remain liquid.
Part C: No, -49 is less than -40, so the gas would have frozen.
Answer:
Step-by-step explanation:
Answer: 1) 36 m and 60 m^2 2) 15π/2 + 10 m and 75π/4 m^2
Step-by-step explanation:
Using the pythagorean theorem in the first question, we get that the slope is 10 m so the perimeter = 10 + 14 + 6 + 6 = 36 m and the area is
(14 + 6)*6/2 = 60 m^2
So in the next question, the arc of the circle has a length of
2π*5*3/4 = 15π/2
So the perimeter is 15π/2 + 5 + 5 = 15π/2 + 10 m
And the area is 3/4*π*5*5=75π/4 m^2
Hope it helps
Answer:
83 - x = 72
x= 11 (if you need it)
Step-by-step explanation:
You wanted an expression, correct?