All categories

2 years ago

Four friends attend a school play

Mathematics

1 answer:

malfutka [58]2 years ago

4 0

Answer:

And then they have fun, by making the actors laugh on stage.

Step-by-step explanation:

lol me

You might be interested in

Find the solution of the given initial value problem in explicit form. y′=(1−5x)y2, y(0)=−12 Enclose numerators and denominators

Nata [24]

Answer:

The solution is $y=-\frac{12}{12x-30x^2+1}$ .

Step-by-step explanation:

A first order differential equation $y'=f(x,y)$ is called a separable equation if the function $f(x,y)$ can be factored into the product of two functions of $x$ and $y$ :

$f(x,y)=p(x)h(y)$

where $p(x)$ and $h(y)$ are continuous functions.

We have the following differential equation

$y'=(1-5x)y^2, \quad y(0)=-12$

In the given case $p(x)=1-5x$ and $h(y)=y^2$ .

We divide the equation by $h(y)$ and move $dx$ to the right side:

$\frac{1}{y^2}dy\:=(1-5x)dx$

Next, integrate both sides:

$\int \frac{1}{y^2}dy\:=\int(1-5x)dx\\\\-\frac{1}{y}=x-\frac{5x^2}{2}+C$

Now, we solve for $y$

$-\frac{1}{y}=x-\frac{5x^2}{2}+C\\-\frac{1}{y}\cdot \:2y=x\cdot \:2y-\frac{5x^2}{2}\cdot \:2y+C\cdot \:2y\\-2=2yx-5yx^2+2Cy\\y\left(2x-5x^2+2C\right)=-2\\\\y=-\frac{2}{2x-5x^2+2C}$

We use the initial condition $y(0)=-12$ to find the value of C.

$-12=-\frac{2}{2\left(0\right)-5\left(0\right)^2+2C}\\-12=-\frac{1}{c}\\c=\frac{1}{12}$

Therefore,

$y=-\frac{2}{2x-5x^2+2(\frac{1}{12})}\\y=-\frac{12}{12x-30x^2+1}$

4 0

2 years ago

What is the graph of y=-(x-2)^3-5

natulia [17]

When x=0,
y=-(0-2)^3-5
y=3

When y=0,
(x-2)^3=5
x-2= +/- 5^1/3
x= +/- 5^1/3 +2
x= 3.70997 or x=0.29002

To find the turning point at y, substitute the information that you have found above.

y=-(3.70997-2)^3-5
y=-9.99994

Find the mid-point next as mid-point is also the turning point.

(3.70997+0.29002)÷2=1.999995

Hence, Turning point is (1.999995, 9.99994)

Plot a graph using turning point, y value and the 2-x values.

6 0

3 years ago

Which of the following is not always true for a function? A. Each x-value has only one y-value. B. The range is the y-values. C.

nignag [31]

Answer:

Step-by-step explanation:

A is True

B is True

D is true

3 0

2 years ago

4. Is the point (3,-4) a solution to the given system? Justify your answer.

Zigmanuir [339]

Answer: No, it is not a solution

==========================================================

Explanation:

The point (3,-4) means that x = 3 and y = -4 pair up together

Let's plug these x,y values into each equation

Starting with the first equation, we get,

y = 4x-16

-4 = 4(3)-16 ... x replaced with 3; y replaced with -4

-4 = 12-16

-4 = -4 .... this is a true statement

Repeat for the second equation

y = 2x-6

-4 = 2(3)-6

-4 = 6-6

-4 = 0 ... this is false

Since we get a false statement, this means (3,-4) is not on the line y = 2x-6, which means that overall (3,-4) is not a solution to the system of equations. The point (3,-4) must make both equations true for it to be a solution.

5 0

2 years ago

sanjay's dog weighs 46 pounds on earth multiply the dogs earth weight by 0.38 to find how much it would weigh on mars, and by 2.

Roman55 [17]

The dog weighs 17.48 pounds on Mars and 108.56 pound on Jupiter. Therefor, it will weigh 91.08 pounds less on Mars than on Jupiter.

6 0

2 years ago