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Alex787 [66]
3 years ago
13

PLEASE ANSWER I WILL GIVE BRAINLIEST PLEASE ANSWER BOTH!!

Mathematics
1 answer:
garri49 [273]3 years ago
7 0

Answer:

t = 130s

Step-by-step explanation:

s = 3.9 * 10^{7} km

v = 3 * 10^{5} km/s

t = ?

t = \frac{s}{v}

t = \frac{3.9 * 10^{7} km}{3 * 10^{5}km/s }

t = 130 s

If the speed signal sent was actually less, meaning that it would take more time to signal arrives from Earth to Mars. The lower the speed, the higher the time.

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Hector's service club is raising money by wrapping presents in the mall. The function f\left(x\right)=3xf(x)=3x describes the am
mestny [16]

Given:

The function f(x) describes the amount of money, in dollars, the club will earn for wrapping x presents.

f(x)=3x

To find:

The f(658).

Solution:

We have,

f(x)=3x

Substitute x=658 to find the value of f(658).

f(658)=3(658)

f(658)=1974

It means, the club will earn $1974 for wrapping 658 presents.

Therefore, f(658)=1974.

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2 years ago
Distributive property <br><br> 5(871)
Rama09 [41]
5(871)=5 x 13 x 67=4355
6 0
3 years ago
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Here are two polygons on a grid.
NNADVOKAT [17]

Answer:

No.

Step-by-step explanation:

For polygon PQRST to be considered a scaled copy of polygon ABCDE, it means every segments of polygon ABCDE were increased proportionally by a scale factor.

The segments in polygon PQRST were not gotten using the same scale factor, hence, it is not a scaled copy of the original polygon, ABCDE.

Segment CD = 2 units, it corresponds to segment RS = 4 units. Scale factor = RS/CD = 4/2 = 2

Segment BC = 1 unit, it corresponds to segment QR = 1 unit. Scale factor = QR/BC = 1/1 = 1 units.

Varying scale factor shows polygon PQRST is not a scaled copy of polygon ABCDE.

7 0
3 years ago
An object is acted upon by the forces F1=&lt;10​,6​,4&gt; and F2=&lt;0​,3​,9&gt;. Find the force F3 that must act on the object
murzikaleks [220]

\vec F_3=\langle x,y,z\rangle is a force vector such that

\vec F_1+\vec F_2+\vec F_3=\vec0

\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle

\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13

So the missing force is

\boxed{\vec F_3=\langle-10,-9,-13\rangle}

8 0
2 years ago
Find the real solution(s) by solving for x (round any decimals to the nearest 100th);<br> 5x = 320
baherus [9]

Answer:

x=64

Step-by-step explanation:

5x = 320

Divide each side by 5

5x/5 = 320/5

x=64

6 0
3 years ago
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