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Anika [276]
3 years ago
9

Sam is filling up his pool. The water hose filled the 315 gallon pool in 45 minutes. At what rate did the hose fill the pool in

gallons per minute?
Mathematics
2 answers:
scoray [572]3 years ago
6 0

Answer:

rate = 7 gallons per minute

Step-by-step explanation:

rate filled is the total amount divided by the time

rate = 315 gallons/ 45 minutes

rate = 7 gallons per minute

Serhud [2]3 years ago
3 0

Answer:

7 gallons per minute

Step-by-step explanation:

315/45 = 7

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Which of the following statements is false?
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6.5<6.05, this one is false

Step-by-step explanation:

look at the Statement and the numbers, it is false through my calculation

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3 years ago
Eigthy millimetes as a percentage of one metre is<br>8<br>80<br>800<br>8000​
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Answer:

8%.

Step-by-step explanation:

There are 1000 millimeters in 1 meter.

So the percentage is (80/1000) * 100

= 80/10

= 8%.

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Give the domain and range.
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The correct answer is a.

Step-by-step explanation:

The domain is the plotted points on the x-axis.

The range is the plotted points on the y-axis.

(-3, 3), (0, 0), (2, -2)

Domain {-3, 0, 2}; Range: {3, 0, -2}

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3 years ago
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wo race car drivers Ryan and Philip were taking laps around the race track. It was noted that Ryan drove 52.5 miles in the same
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Answer:bvhj

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Step-by-step explanation:

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4 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

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2 years ago
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