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luda_lava [24]
3 years ago
13

If f(x) = │(x² – 50)│, what is the value of f(-5) ?

Mathematics
2 answers:
Tju [1.3M]3 years ago
6 0
Have a nice day :)
_______________

AleksandrR [38]3 years ago
5 0
F(x) = │(x² – 50)│

f(-5) = │(-5² – 50)│

f(-5) = │(25 – 50)│

f(-5) = │(-25)│

f(-5) = 25

\framebox[1.1\width]{ f (-5)    =  25} \par \\  \\ \framebox[1.1\width]{ Good Luck} \par
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Noah wants to create a floor plan that is a scale drawing. The actual length of Wall C is 4 m. To represent Wall C, Noah draws a
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Step-by-step explanation:

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Find the circumferences of the two circles circle a has a radius of 21 meters and circle b has a radius of 28 meters Is the rela
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Answer:

The circumference for <em>circle a</em> is \\ C = 131.9430m.

The circumference for <em>circle b</em> is \\ C = 175.9240m.

The relationship between the radius of a circle and the circumference (the distance around the circle) is constant and is the same for all circles and can be written as \\ \frac{C}{r} = 2\pi or, in a less familiar form, \\ \frac{r}{C} = \frac{1}{2\pi}. The number \\ \pi is constant for all circles and has infinite digits, \\ \pi = 3.14159265358979.....

Step-by-step explanation:

The <em>circumference</em> of a circle is given by:

\\ C = 2*\pi*r [1]

Where

\\ C is the circle's circumference.

\\ r is the radius of the circle.

And

\\ \pi = 3.141592.... is a constant value (explained below)

We can say that <em>the distance around the circle</em> is the circle's <em>circumference</em>.

The circumferences of the two circles given are:

Circle a, with radius equals to 21 meters (\\ r = 21m).

Using [1], using four decimals for \\ \pi, we have:

\\ C = 2*\pi*r

\\ C = 2*3.1415*21m

\\ C = 131.9430m

Then, the circumference for <em>circle a</em> is \\ C = 131.9430m.

Circle b, with radius equals to 28 meters (\\ r = 28m).

\\ C = 2*3.1415*28m

\\ C = 175.9240m

And, the circumference for <em>circle b</em> is \\ C = 175.9240m.

We know that

\\ 2r = D

That is, the diameter of the circle is twice its radius.

Then, if we take the distance around the circle and we divided it by \\ 2r

\\ \frac{C}{2r} = \frac{C}{D} = \pi

This ratio, that is, the relationship between the distance around the circle (circumference) and <em>the diameter</em> of a circle is \\ \pi and is constant for all circles. This result is called the \\ \pi number, which is, approximately, \\ \pi = 3.141592653589793238.... (it has infinite number of digits).

We can observe that the relationship between the radius of a circle and the circumference is also constant:

\\ \frac{C}{2r} = \frac{C}{D} = \pi

\\ \frac{C}{2r} = \pi

\\ \frac{C}{r} = 2\pi

However, this relationship is \\ 2\pi.

We can rewrite it as  

\\ \frac{r}{C} = \frac{1}{2\pi}

And it is also constant.

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Answer: Never true. 24 times 12 is 288, however the LCM for them is 3. 8 times 20 is 160, however the LCM for them is 2.

Step-by-step explanation:

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