Washington street and Vindale avenue intersect at a right angle. if the diagonal distance across the intersection is 15 meters a
nd washington street is 9 meters wide, how wide is vindale avenue?
1 answer:
A^2+b^2=c^2
9^2+b^2=15^2
81+b=225
b= √144
b=12
I’m pretty sure it’s 12, hope this makes sense :)
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