Answer:
Bridget's first fish =f = 5 ounces
Bridget's dad first fish weighs 17 ounces
Step-by-step explanation:
Solution:
Bridget's fishes:
f ounces
2f ounces
3f+2 ounces
1/2f ounces
3/5f ounces
Total= f +2f + (3f+2) + 1/2f +3/5f
=3f + 3f + 2 + 5f+6f/10
=6f + 2 + 11f/10
=60f+11f/10 +2
=71/10f +2
Bridget's dad fishes
3f+2
4/5f
2f+4
1/2f
Total =(3f+2) + (2f+4) + 4/5f +1/2f
=3f+2+2f+4 + 8f+5f/10
=5f + 6 + 13/10f
= 50f+13f/10 + 6
=63/10f +6
Equate the total weight
71/10f +2=63/10f +6
Collect like terms
71/10f - 63/10f =6-2
71f-63f/10 = 4
8f/10=4
Cross product
8f=40
Divide both sides by 8
f=5
Bridget's first fish =f = 5 ounces
Bridget's dad first fish = 3f +2
=3(5)+2
=15+2
=17 ounces
Bridget's dad first fish weighs 17 ounces
I’m not sure never took that test
Answer:
Population mean = 7 ± 2.306 × 
Step-by-step explanation:
Given - A university researcher wants to estimate the mean number
of novels that seniors read during their time in college. An exit
survey was conducted with a random sample of 9 seniors. The
sample mean was 7 novels with standard deviation 2.29 novels.
To find - Assuming that all conditions for conducting inference have
been met, which of the following is a 94.645% confidence
interval for the population mean number of novels read by
all seniors?
Proof -
Given that,
Mean ,x⁻ = 7
Standard deviation, s = 2.29
Size, n = 9
Now,
Degrees of freedom = df
= n - 1
= 9 - 1
= 8
⇒Degrees of freedom = 8
Now,
At 94.645% confidence level
α = 1 - 94.645%
=1 - 0.94645
=0.05355 ≈ 0.05
⇒α = 0.5
Now,

= 0.025
Then,
= 2.306
∴ we get
Population mean = x⁻ ±
×
= 7 ± 2.306 × 
⇒Population mean = 7 ± 2.306 × 
Answer:
3
Step-by-step explanation:
Those are called "even numbers".
Also, I guess, "multiples of 2" .