Step-by-step explanation:
Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.
The standard error is SE = s/√n = 62.6/√50 = 8.85.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
180.56 ± 1.960 × 8.85
180.56 ± 17.35
(163, 198)
Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.
The standard error is SE = s/√n = 49.2/√50 = 6.96.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
152.96 ± 1.960 × 6.96
152.96 ± 13.64
(139, 167)
Answer:
do you have any options for this question just to check??
V = 126 if that's what you're looking for
Answer:
Step-by-step explanation:
Note that 128 = 64*2. The square root of 128 is thus 8sqrt(2). Answer B is the only one that could be correct.
You can work out that K≈2.9262 and then plugging this in gives us θ≈2.34∘