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enot [183]
3 years ago
9

How many sheets of plywood do I need for a 1020 square foot area​

Mathematics
1 answer:
lara [203]3 years ago
3 0

Answer:

assuming no scrap loss, 32 pieces of standard 4x8 sheets

Step-by-step explanation:

1020/(8x4)=31.875

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a shipping box will be filled with two different machine parts. one type of machine part weights 0.15 ponds and the other weight
gulaghasi [49]
\frac{x}{2} =0.15 hope so this helps

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Answer:

A) Both estimates are slightly larger, so it is reasonable.

Step-by-step explanation:

Since 1/2 = 5/10

And 1/5 = 8/40

<u>Both estimates are larger</u>

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Whats 407 divided by 47..<br>​
vovangra [49]

Answer:

8.65957446809

Step-by-step explanation:

8\frac{31 }{47}   8.7

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Match the equations of the lines with their graphs.
nika2105 [10]

Answer:1. y = 2x - 3

2. y= 2x + 3

3. y = -2x + 3

4. y = -2x - 3

Step-by-step explanation:

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3 years ago
The list below shows the Highlight in inches of the player on a man college basketball team
boyakko [2]

We have the data set:

{79, 83, 82, 78, 79, 77, 80, 73, 82, 72}

This data set has 10 items.

To complete the data summary is helpful to sort the data:

{72, 73, 77, 78, 79, 79, 80, 82, 82, 83}

The minimum value is 72.

<em>The quartile divides the data set in 4 parts. </em>

<em>The first quartile is the value for which 25% of the data is below.</em>

<em>The second quartile is the value for which 50% of the data is below. The second quartile is equivalent to the median.</em>

<em>The third quartile is the value for which 75% of the data is below.</em>

In this data set, as its size is a even number, the quartile fall between two positions, so we will calculate the average of this numbers.

The first quartile will fall in the position 0.25*10=2.5. Then we can calculate the 1st quartile as the average between the 2nd and 3rd number of the data set.

This values are 73 (2nd position) and 77 (3rd position), so the average is:

Q_1=\frac{73+77}{2}=75

We can repeat this with the other quartiles:

\begin{gathered} Q_2=M=\frac{79+79}{2}=79 \\ Q_3=\frac{82+82}{2}=82 \end{gathered}

Then:

The first quartile is 75.

The median (second quartile) is 79.

The third quartile is 82.

The maximum value is 83.

7 0
1 year ago
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