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Alborosie
3 years ago
13

three positive whole numbers have a sum of 48. The second number is 5 times the first and the third number is twice the second n

umber. What are the three numbers?
Mathematics
2 answers:
Mademuasel [1]3 years ago
5 0

Answer:

3, 15 and 30

Step-by-step explanation:

Let the first number be x

Second number is 5 times the first number = 5x

Third number is twice the second number = 2×5x = 10x

The equation becomes;

x + 5x + 10x = 48

16x = 48

x = 48 ÷ 16

x = 3

Therefore the three numbers are x = 3,  5x = 15 and 10x = 30

ira [324]3 years ago
5 0

Answer:

3,15 and 30

Step-by-step explanation:

Let the number be A , B and C.

The sum of the three positive numbers are 48

That’s

A + B + C = 48

The second number is 5 times the first

That’s

B = 5A

The third number is twice the second

That’s

C = 2 x 5A = 10A

We now have

A + B + C = 49

B = 5A

C = 10A

Now substitute 5A for B and 10A for C into the first equation

We have

A + B + C = 48

A + 5A + 10A = 48

16A = 48

Divide both sides by 16 to get A

16A/16 = 48/16

A = 3

Recall

B = 5A

So

B = 5 x 3

B = 15

Also,

C = 10A

Therefore

C = 10 x 3

C = 30

The numbers are 3,15 and 30

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