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3 years ago

You roll a pair of fair dice. Classify the probability for each of the outcomes as Impossible, Unlikely, Likely, or Certain.

Mathematics

1 answer:

jek_recluse [69]3 years ago

8 0

Answer:

THE DIFFERENCE OF THE NUMBERS IS 6~ likely

THE SUM ON EACH DIE IS 5~ unlikely

THE NUMBER ON EACH DIE IS A WHOLE NUMBER~ Certain

THE NUMBER ON EACH DIE IS LESS THAN 6~ likely

THE SUM OF THE NUMBERS IS 14 OR GREATER~ impossible

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n 2000 the population of a small village was 2,400. With an annual growth rate of approximately 1.68%, compounded continuously,

Nitella [24]

Answer:

The population would be 3358

Step-by-step explanation:

Since, exponential growth function if the growth is compound continuously,

$A = Pe^{rt}$

Where,

P = initial population,

r = growth rate per period,

t = number of periods,

Given,

The population in 2000, P = 2,400,

Growth rate per year = 1.68% = 0.0168,

Number of years from 2000 to 2020, t = 20,

Thus, the population in 2020,

$A=2400 e^{0.0168\times 20}$

$=2400 e^{0.336}$

$= 3358.4136$

$\approx 3358$

6 0

3 years ago

A composite shape is shown.

kodGreya [7K]

Answer:

you lost me at composite

Step-by-step explanation:

Have a good day

3 0

3 years ago

Read 2 more answers

Pythagorean theorem (picture provided)

e-lub [12.9K]

The answer is of option D.

Hope this will help u...:)

8 0

3 years ago

Read 2 more answers

A machine packs 2/5 of a box every 1/2 minute. What is the number of boxes per minute packed? Why?

Alla [95]

If it is packed 2/5 in 1/2 minutes

1 minute =2/5*2=4/5 or 0.8 boxes/min

4 0

3 years ago

PLZ HELP!!! Use limits to evaluate the integral.

Marrrta [24]

Split up the interval [0, 2] into n equally spaced subintervals:

$\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]$

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

$r_i=\dfrac{2i}n$

where $1\le i\le n$ . Each interval has length $\Delta x_i=\frac{2-0}n=\frac2n$ .

At these sampling points, the function takes on values of

$f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}$

We approximate the integral with the Riemann sum:

$\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3$

Recall that

$\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4$

so that the sum reduces to

$\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}$

Take the limit as n approaches infinity, and the Riemann sum converges to the value of the integral:

$\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}$

Just to check:

$\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28$

4 0

3 years ago