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kap26 [50]
4 years ago
15

What is the median of 74,83,79,62,65,73

Mathematics
1 answer:
Allisa [31]4 years ago
4 0

Answer:

Step-by-step explanation:

Median: 73.5

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Give ur answer in standard form. <br>3 x 10^4 ÷6 x 10^-4<br>​
Anni [7]

Answer:

5.0×10⁷

Step-by-step explanation:

(3÷6)×(10⁴÷10^-4)

(0.5)×(10⁸)

5.0×10^-1×10⁸

5.0×10⁷

7 0
2 years ago
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Which of the following is the quadratic parent function?
kipiarov [429]

Answer:

F(x)=x^2

Step-by-step explanation:


8 0
3 years ago
19,432÷x=48 Remainder 232 (Plz help its for my hw that's due tmrw)
Neko [114]

Answer:

x = 404.83

Step-by-step explanation:

The given expression is :

19,432÷x=48 ...(1)

We need to find the value of x.

\dfrac{19,432}{x}=48

Cross multiplying both sides,

19,432=48x

Dividing both sides by 48

\dfrac{19,432}{48}=x\\\\x=404.83

So, the value of x is 404.83.

4 0
3 years ago
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Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)
BartSMP [9]

Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

so distance between A(-5,4) and B(3,4) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

So AB is 8 unit apart.

For B(3,4) and C(3,-5).

\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

so fourth bush 9 units below of A.

8 0
1 year ago
What is the inverse of the function f(x) = 2x – 10?
Nadusha1986 [10]

Answer:

f⁻¹(x) = (1/2)x +5

Step-by-step explanation:

In y = f(x), swap the variables, then solve for y. The expression you get is f⁻¹(x).

... y = 2x -10

... x = 2y -10 . . . . . . swapped variables

... x +10 = 2y . . . . . add 10

... (1/2)x + 5 = y . . . . divide by 2

... f⁻¹(x) = (1/2)x + 5 . . . . . . rewrite using function notation

6 0
3 years ago
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