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3 years ago

What is the median of 74,83,79,62,65,73

Mathematics

1 answer:

Allisa [31]3 years ago

4 0

Answer:

Step-by-step explanation:

Median: 73.5

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A contractor bought 7.6 ft2 of sheet metal. She has used 3.5 ft2 so far and has $123 worth of sheet metal remaining. The equati

Sergio039 [100]

Answer:

Sheet metal remaining = 4.1x

cost per square foot of sheet metal = $30

Step-by-step explanation:

Total sheet metal bought = 7.6 ft2

Total sheet metal used = 3.5 ft2

Given equation:

7.6x − 3.5x = 123

Where,

x = cost per square foot

7.6x − 3.5x

Sheet metal remaining = 4.1x

7.6x − 3.5x = 123

4.1x = 123

x = 123 / 4.1

x = $30

Cost per square foot = $30

5 0

2 years ago

The lowest point on the parabola is (0, -1).

astraxan [27]

Answer:

vertex

Step-by-step explanation:

vertex

If the coefficient a > 0, then the parabola opens upward and the vertex is the lowest point on the parabola. We say that k is the minimum value of the quadratic function. On the other hand, if the coefficient a < 0, then the parabola opens downward and the vertex is the highest point on the parabola.

3 0

2 years ago

1 +100000 what is the best answer

serg [7]

Answer:

10001 is the answer to your Question

5 0

2 years ago

What is the answer to 3/4 divided by 9/10

meriva

The answer is <span>0.00833333333</span>

3 0

3 years ago

Read 2 more answers

A machine produces metal pieces that are cylindrical in shape. A sample of pieces is taken, and the diameters are found to be 1.

Ghella [55]

Answer:

99% confidence interval: (0.97816,1.03184)

Step-by-step explanation:

We are given the following data set:

1.01, 0.97, 1.03, 1.04, 0.99, 0.98, 0.99, 1.01, 1.03

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{9.05}{9} = 1.005$

Sum of squares of differences = 0.00001975308642 + 0.001264197531 + 0.000597530864 + 0.001186419753 + 0.0002419753088, + 0.00065308642 + 0.0002419753088 + 0.00001975308642 + 0.000597530864 = 0.0048

$S.D = \sqrt{\frac{0.0048}{8}} = 0.024$

Confidence interval:

$\bar{x} \pm t_{critical}\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 8}~\alpha_{0.01} = \pm 3.355$

$1.005 \pm 3.355(\frac{0.024}{\sqrt{9}} ) = 1.005 \pm 0.02684 = (0.97816,1.03184)$

6 0

3 years ago