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Evgen [1.6K]
4 years ago
13

How do you successfully solve 9 divided by 0.

Mathematics
2 answers:
gogolik [260]4 years ago
4 0
Well solving 9 divide by 0 is easy.. It's like multiply everything by zero, you will still get 0.so dividing 9 x 0 will give you zero
Alex787 [66]4 years ago
3 0
Well Division is really like multiplication so if you multiply 1 times 0 its automatically 0 so that's the exact same if you divide something with 0 its always 0
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A recipe calls for 11 cups of flour, 3 cup of white sugar, and 1 cup of brown sugar. 248
Alex Ar [27]

Step-by-step explanation:

complete the number line

8 0
3 years ago
Which point-slope form equation represents a line that passes through (3,-2) with a slope of -4/5
son4ous [18]

Answer:

y + 2 = - \frac{4}{5}(x - 3)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = - \frac{4}{5} and (a, b) = (3, - 2), hence

y - (- 2) = - \frac{4}{5}(x - 3), that is

y + 2 = - \frac{4}{5}(x - 3)

3 0
4 years ago
Can you answer this PLEASEEEE​
WINSTONCH [101]

The figure is a parallelogram so the facing sides have equal size which means :

DE = GF & DG = EF

-------------------------------------------------------------

DE = 3x - 1 , GF = 2x + 11

DE = GF ==》 3x - 1 = 2x + 11

subtract sides minus 2x

==》- 2x + 3x - 1 = - 2x + 2x + 11

collect like terms

==》 x - 1 = 11

add sides 1

==》 x - 1 + 1 = 11 + 1

==》 x = 12

-------------------------------------------------------------

As we found : DG = EF

DG = 2x - 3 So EF = 2x - 3

To find the size of EF, we need to put the value of x (which we found above) instead x.

EF = 2 × ( 12 ) - 3 ==》 EF = 24 - 3

==》 EF = 21

And we're done...

8 0
3 years ago
HELP FAST ILL MAKE BRAINIEST Mr. McClellan compared the weights (in pounds) of pairs of elk antlers dropped at Mount St Helens N
Anika [276]
a.1 Line plot for <span>eight of elk antler pairs at Mount St Helens NVM

</span>The diagram is shown in figure 1.

a.2 Weight of elk antler pairs at Rocky Mountain NP

The diagram is shown in figure 2.

b. Calculate the following for each set of data:

We can found the mean (µ) of a set of data points by adding them up and dividing by the number of data points.

b.1 Purple Mean:

Set: \{34, 34, 30, 30, 30, 28, 28, 26\} \rightarrow  \frac{34+34+30+30+30+28+28+26}{8} \rightarrow \boxed{\mu=30}

b2. Red 
Mean:

Set: \{40, 38, 36, 36, 36, 36, 34, 32\} \rightarrow \frac{40+38+36+36+36+36+34+32}{8} \rightarrow \boxed{\mu=36}

b.3 
<span>Red Median
</span>
The Median is the middle of a sorted list of numbers. <span>The median of a finite list of numbers can be found by arranging all the numbers from smallest to greatest. So, arranging the red set we have:
</span><span>
\{32, 34, 36, 36, 36, 36, 38, 40\}

Given that the number of elements is pair, the median can be solved as follows:

</span>\overline{x}=\frac{x_{(n/2)}+ x_{((n/2)+1)}}{2}

∴ n=8
∴ x_{(n/2)}=x_{(4)}=36
∴ x_{((n/2)+1)}=x_{(5)}=36

Then:

\overline{x}=\frac{36+36}{2}=36

b.4 Purple MAD

The Mean Absolute Deviation (MAD) is when you find the distance of each data point from the mean and then find the mean <span>of those distances. So:
</span>
\{34, 34, 30, 30, 30, 28, 28, 26\} has \mu=30
distances=\{4, 4, 0, 0, 0, 2, 2, 4\} \rightarrow \frac{4+4+0+0+0+2+2+4}{8}= \boxed{MAD=2}

b.5 Red MAD

\{40, 38, 36, 36, 36, 36, 34, 32\} has \mu=36
distances=\{4, 2, 0, 0, 0, 0, 2, 4\} \rightarrow \frac{4+2+0+0+0+0+2+4}{8}= \boxed{MAD=1.5}

 c. Calculate the means-to-MAD ratio for the two areas of collection

c.1 Purple set:

The ratio is the<span> relationship between the mean and the MAD indicating how many times the first number contains the second, so:
</span>
\frac{\mu}{MAD}= \frac{30}{2}=\boxed{15}

c.2 Red set:

\frac{\mu}{MAD}= \frac{36}{1.5}=\boxed{24}

d. What inference can be made about the areas in regard to weight of dropped elk antlers? 

MAD tells us how far, on average, all values are from the middle. So, in the example weight of elk antler pairs at Mount St Helens NVM are, on average, 2 away from the middle. On the other hand, weight of elk antler pairs at Rocky Mountain NP are, on average, 1.5 away from the middle. So, we can assure that elk antler pairs at Rocky Mountain NP weighs more than elk antler pairs at Mount St Helens NVM.


3 0
3 years ago
Factor g(x) = 3x(2) - 27
11111nata11111 [884]
The Answer For Factor g(x) =57
4 0
3 years ago
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