Question

A spinner has 4 equally sized sectors that are numbered 3, 3, 4 and 6. The spinner is spun twice and the sum of the outcomes is found.
A fair decision is to be made about which one of 4 vacation destinations will be planned, using the sum of the outcomes.

The vacation destination options are New Mexico, Alaska, Puerto Rico and London.

Which description accurately explains how a fair decision can be made in this situation?




If the sum is 6, the vacation destination will be London. If the sum is 7, the vacation destination will be Alaska. If the sum is 9, the vacation destination will be New Mexico. If the sum is 8, 10 or 12, the vacation destination will be Puerto Rico.

If the sum is 10, the vacation destination will be London. If the sum is 7, the vacation destination will be Alaska. If the sum is 9, the vacation destination will be New Mexico. If the sum is 6, 8 or 12, the vacation destination will be Puerto Rico.

If the sum is 6, the vacation destination will be London. If the sum is 7, the vacation destination will be Alaska. If the sum is 10, the vacation destination will be New Mexico. If the sum is 8, 9 or 12, the vacation destination will be Puerto Rico.

If the sum is 6, the vacation destination will be London. If the sum is 8, the vacation destination will be Alaska. If the sum is 9, the vacation destination will be New Mexico. If the sum is 7, 10 or 12, the vacation destination will be Puerto Rico.

Answer 1

Answer:

first option:

If the sum is 6, the vacation destination will be London. If the sum is 7, the vacation destination will be Alaska. If the sum is 9, the vacation destination will be New Mexico. If the sum is 8, 10 or 12, the vacation destination will be Puerto Rico.

Step-by-step explanation:

To solve this problem we need to find the probability of each sum.

The pairs of results we can have is:

(3,3), (3,3), (3,4), (3,6),

(3,3), (3,3), (3,4), (3,6),

(4,3), (4,3), (4,4), (4,6),

(6,3), (6,3), (6,4), (6,6).

The sums are:

6, 6, 7, 9,

6, 6, 7, 9,

7, 7, 8, 10,

9, 9, 10, 12.

We have 4 sixs, 4 sevens, 4 nines, 1 eight, 2 ten and 1 twelve

So the first option shows a fair decision, as each decision has 4 possible values to happen.