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4 years ago

I am bad in fraction math. can you please help me. with proper explanation. Thank you!

Mathematics

2 answers:

fredd [130]4 years ago

8 0

Answer:

1 - 8/9 + 4/9 = 9/9 -8/9 +4/9 = (9-8+4)/9 = 5/9

Step-by-step explanation:

Feliz [49]4 years ago

4 0

Answer:

The answer is 5/9.

Step-by-step explanation:

First, you have to make all the denorminator of the fractions the same by multultiplying :

$1 - \frac{8}{9} + \frac{4}{9}$

$= \frac{1}{ 1} - \frac{8}{9} + \frac{4}{9}$

$= \frac{1 \times 9}{1 \times 9} - \frac{8}{9} + \frac{4}{9}$

$= \frac{9}{9} - \frac{8}{9} + \frac{4}{9}$

Next, you have to make it into 1 fraction and simplify :

$\frac{9}{9} - \frac{8}{9} + \frac{4}{9}$

$= \frac{9 - 8 + 4}{9}$

$= \frac{5}{9}$

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Answer:

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Step-by-step explanation:

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3 years ago

Determine the radius and center of the circle with the following equation x^2+y^2-12x+24y-10=6

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Answer:

Center: (6, -12)

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Step-by-step explanation:

Complete the squares

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2 years ago

Solve the following one-step inequality : -12+x ≥9 I GIVE BRAINLEST I KNOW I SPELL WRONG

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3 years ago

Read 2 more answers

Write the decimal 0.8¯¯¯ as a fraction in simplest form.

denis23 [38]

Answer: 4/5

Step-by-step explanation:

0.8 is 8 tenths which is 8/10 in fraction form

8/10 with both sides divided by two is 4/5

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3 years ago

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e^−2

Mekhanik [1.2K]

Answer:

x=1

y=s

z=1

Step-by-step explanation:

(x, y, z)=(1, 0, 1)

Substitute 0 for y

$y = e^{-2t} *sin 4t\\0 = e^{-2t} *sin 4t\\\\0 = e^{-2t} *(\frac{e^{4t}-e^{-4t}}{2j} )\\0 = e^{-2t} *(e^{4t}-e^{-4t} )\\0 = e^{-2t} *e^{4t}*(1-e^{-8t} )\\\\0 = e^{2t}*(1-e^{-8t} )\\\\\\Either \\0 = e^{2t}\\t = -inf\\or\\0 = (1-e^{-8t} )\\(e^{-8t} ) = 1\\ -8t = ln(1) =0\\t=0\\\\$

Confirming if t=0 satisfy the other equation

x = e^−2t cos 4t = e^−2(0)cos(4*0)

= e^(0)cos(0) = 1

z = e^−2t = e^−2(0) = 0

Therefore t=0 satisfies the other equation

Finding the tangent vector at t=0

$\frac{dx}{dt}=-2te^{-2t} cos4t + e^{-2t}(-4sin4t)=-2(0)e^{-2(0)} cos4(0) + e^{-2(0)}(-4sin4(0))=0\\\\ \frac{dy}{dt} =-2te^{-2t} sin4t + e^{-2t}(4cos4t)=-2(0)e^{-2(0)} sin4(0)+ e^{-2(0)(4cos4(0)) }= 1\\\\\frac{dz}{dt} = -2te^{-2t} = -2(0)e^{-2(0)} = 0$

The vector equation of the tangent line is

(1, 0, 1) +s(0,1,0)= (1, s, 1)

The parametric equations are:

x=1

y=s

z=1

6 0

3 years ago

I am bad in fraction math. can you please help me. with proper explanation. Thank you! ​

I am bad in fraction math. can you please help me. with proper explanation. Thank you!