All categories

3 years ago

Sales increased by 1/2 last month. If the sales from the previous month were $152,850 what were last months sales?

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

6 0

Answer

229275

Step-by-step explanation:

Take the previous month sales and cut that in half then add them to the same sales you just cut in half because they've increased by 1/2 and or 0.5

You might be interested in

Jamie jogged a total distance of 6 and 1 over 2 miles during the months of March and April. If Jamie only jogged 1 over 6 mile e

Talja [164]

For this kind of problems, first find the method to solve, then face the fractions.

If I jog 100 miles in a year, and I do 2 miles a day. How many days did I jog?
We know easily that it is 100 days/ 2 miles/day = 50 days.
So the number of days is total distance / how much a day, or
(6 1/2) divided by (1/6)

7 0

3 years ago

As part of quality-control program, 3 light bulbs from each bath of 100 are tested. In how many ways can this test batch be chos

hichkok12 [17]

Answer:

<h3>By 161700 ways this test batch can be chosen.</h3>

Step-by-step explanation:

We are given that total number of bulbs are = 100.

Number of bulbs are tested = 3.

Please note, when order it not important, we apply combination.

Choosing 3 bulbs out of 100 don't need any specific order.

Therefore, applying combination formula for choosing 3 bulbs out of 100 bulbs.

$^nCr = \frac{n!}{(n-r)!r!}$ read as r out of n.

Plugging n=100 and r=3 in above formula, we get

$^100C3 = \frac{100!}{(100-3)!3!}$

Expanding 100! upto 97!, we get

= $\frac{100\times 99\times 98\times 97!}{97!3!}$

Crossing out common 97! from top and bottom, we get

= $\frac{100\times 99\times 98}{3!}$

Expanding 3!, we get

= $\frac{100\times 99\times 98}{3\times 2\times 1}$

= 100 × 33 × 49

= 161700 ways.

<h3>Therefore, by 161700 ways this test batch can be chosen.</h3>

3 0

4 years ago

Please help this is due tomorrow!!

Nikitich [7]

Angel is 8 years old and Alex is 30 years old x-y=30

3 0

3 years ago

Read 2 more answers

What is the arc length of the semicircle

MrMuchimi

Answer:

The arc length of the semicircle is half the circumference of the full circle

8 0

3 years ago

Read 2 more answers

Suppose that a market research firm is hired to estimate the percent of adults living in a large city who have cell phones. 500

Alborosie

Answer:

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.