Answer: the second option.
A binomial experiment is an experiment with only two possible outcomes.
In the first option, there is four poissible outcomes (i.e. ace, king, queen, jack)
In the second option, there are two possible outcomes (i.e. '2 number cubes')
The third option has three possible outcomes (i.e. yes, no, maybe)
In the last option, there are six possible outcomes (i.e. A through F)
Answer:
the ticket will cost 256.28
Step-by-step explanation:
you need to multiply the cost of the ticket 149 by .72 and you get 107.28
then add 149 + 107.28 to get 256.28
Are you sure that is the correct sequence?
dy/dx=2,4,8,12,24
d2y/dx2=2,4,4,12
d3y/dx3=2,0,8
d4y/dx4=-2,8
So there is no constant rate of change so we cannot be certain what order of equation would continue the sequence accurately...
We COULD make d5y/dx5=10 so we COULD make a fifth order equation to create that sequence, however there is no way that we can prove that it is valid beyond the data points given...ie, there is no way to prove what the next term after 62 is.
If you wish to solve for that fifth order forced fit you can set up a system of equations of the form an^5+bn^4+cn^3+dn^2+en+f=a(n) using all of your points (n, a(n))
Answer:
The correct is the little (B) 0.76
Answer:
And we can find the individual probabilities using the probability mass function and we got:
And replacing we got:
Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Solution to the problem
For this case we want this probability:
And we can use the complement rule and we got:
And we can find the individual probabilities using the probability mass function and we got:
And replacing we got: